What is the theoretical yield of sodium chloride for the reaction of 55.0 g na with 67.2 g cl2?

1 answer:

7 0

The chemical reaction would be written as:

2Na + Cl2 = 2NaCl

Since we are given the amounts of the reactants available for reaction, we have to determine the limiting reactant. And use this amount to calculate for the theoretical yield.

55 g Na ( 1 mol / 22.99 g ) = 2.39 mol Na
67.2 f Cl2 ( 1 mol / 70.9 g ) = 0.95 mol Cl2

Therefore, the limiting reactant would be Cl2 since it is the one consumed completely.

0.95 Cl2 ( 1 mol NaCl / 1 mol Cl2) = 0.95 NaCl produced from the reaction

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Pls help I don’t understand at all

galina1969 [7]

Answer:

Mass = 12.48 g

Explanation:

Given data:

Mass of sulfur dioxide = 25.0 g

Mass of sulfur formed = ?

Solution:

Chemical equation:

SO₂ → S + O₂

Number of moles of SO₂:

Number of moles = mass/molar mass

Number of moles = 25.0 g / 64.07 g/mol

Number of moles = 0.39 mol

Now we will compare the moles of SO₂ with S.

SO₂ : S

1 : 1

0.39 : 0.39

Mass of sulfur:

Mass = number of moles × molar mass

Mass = 0.39 mol × 32 g/mol

Mass = 12.48 g

4 0

3 years ago

A piece of silver metal has a mass of 3.687 grams. If the density of silver is 10.5 g/cm, what is the volume of the silver?

GenaCL600 [577]

Answer:

Volume = (0.62 m)^3

Explanation:

If the density of silver is 10.5 g/cm, the volume of the silver is (0.62 m)^3.

3 0

3 years ago

What heat is liberated in the formation of 10.0 grams of sulfur hexafluoride, SF6, from the elements sulfur and fluorine?

tensa zangetsu [6.8K]

Answer:

$Q=-76.7kJ$

Explanation:

Hello,

In this case, for such formation of sulfur hexafluoride, the standard enthalpy of formation is -1220.47 kJ/mol (data extracted from NIST database). Next, we compute the moles in 10.0 grams of sulfur hexafluoride as shown below:

$n_{SF_6}=10.0gSF_6*\frac{1molSF_6}{146.06 gSF_6}=0.0685mol$