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Fiesta28 [93]
2 years ago
10

__________ have an electric charge of -1.60 × 10-19 C (-e).

Chemistry
1 answer:
nignag [31]2 years ago
6 0

Answer:

Electrons have an electric charge of -1.60 × 10-19 C

Explanation:

Neutrinos and Neutrons have 0 e charge.

Protons have an electric charge of 1.60 × 10-19 C

Historically, electrons were assigned a negative charge

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Which scientific law states the relationship between an object's mass, acceleration, and amount of force acting on it? *
jenyasd209 [6]
Newton's second law of motion
5 0
2 years ago
A mixture of gases has 0.3000 mol of CO2, 0.2706 mol of SO2 and 0.3500 mol of water vapor. The total pressure of the mixture is
notka56 [123]

Answer:

Partial pressure SO₂ → 0.440 atm

Explanation:

We apply the mole fraction concept to solve this:

Moles of gas / Total moles = Partial pressure of the gas / Total pressure

Total moles = 0.3 moles of CO₂ + 0.2706 moles of SO₂ + 0.35 moles H₂O

Total moles = 0.9206 moles

Mole fraction SO₂ = 0.2706 moles / 0.9206 moles → 0.29

Now, we can know the partial pressure:

0.29 = Partial pressure SO₂ / Total pressure

0.29 = Partial pressure SO₂ / 1.5 atm

0.29 . 1.5atm = Partial pressure SO₂ → 0.440 atm

8 0
3 years ago
How many atoms of oxygen are in 0.100 miles of silicon dioxide, SiO^2
mixas84 [53]
<span>3.10 moles SiO2 (1 mole Si/1 mole SiO2)(6.022 X 1023/1 mole Si) = 1.87 X 1024
</span><span>= 1.20 X 1023 atoms of oxygen.</span>
7 0
2 years ago
Cal is titrating 50.8 mL of 0.319 M HBr with 0.337 M Ba(OH)2. How many mL of Ba(OH)2 does Cal need to add to reach the equivalen
alexgriva [62]

Answer:

V_{base}=24.04mL

Explanation:

Hello!

In this case, according to the chemical reaction by which HBr reacts with Ba(OH)2:

2HBr+Ba(OH)_2\rightarrow BaBr_2+2H_2O

We can see there is a 2:1 mole ratio between the acid and the base; thus, at the equivalent point we can write:

2M_{base}V_{base}=M_{acid}V_{acid}

Therefore, for is to compute the volume of the used base, we proceed as shown below:

V_{base}=\frac{M_{acid}V_{acid}}{2M_{base}}

And we plug in to obtain:

V_{base}=\frac{0.319M*50.8mL}{2*0.337M}\\\\V_{base}=24.04mL

Best regards!

8 0
3 years ago
Please help me! ASAP
Svetlanka [38]

Answer:

(1) 4- ethyl -6 methyl -2 octyne

5 0
2 years ago
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