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topjm [15]
3 years ago
8

568 muons were counted by a detector on the top of Mount Washington in a one hour period of time. Assuming moving muons keep tim

e at the same rate as stationary muons, then 27 should survive until sea level. The fact that 412 muons were detected by the same equipment at sea level reveals that
A. the stationary clock measures time differently at different altitudes
B. the moving clocks keep time at the same rate as stationary clocks
C. that moving clocks run slower
D. that moving clocks run faster
Physics
2 answers:
AlladinOne [14]3 years ago
6 0
The answer to this question is:

C-"That moving clocks run slower"

Your Welcome :)
Cerrena [4.2K]3 years ago
4 0

Explanation:

The fact that 412 muons were detected by the same equipment at sea level reveals that moving clocks run slower. This is due to the reason of time dilation.

The time dilation slow down time with respect to external observer. The time dilation is caused due to the force of gravity and the velocity with which the object is moving.

Hence, the correct option is (c) "moving clocks run slower".

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1. In a single atom, no more than 2 electrons can occupy a single orbital? A. True

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B.6

3. A neutral atom has a ground state electronic configuration of 1s^2 2s^2. Which of the following statements concerning this atom is/are correct?
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3 years ago
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A good way to demagnitize something
USPshnik [31]

Answer:

heat it up to above 176f or apply alternating current

Explanation:

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Mercury’s natural state is where the atoms are close to each other but are still free to pass by each other in witch states coul
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Liquid is the answer

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3 years ago
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Find the velocity and distance travelled of a car that is accelerating at 3 m/s2 for 4 seconds.
marta [7]

Explanation:

Given:

v₀ = 0 m/s

a = 3 m/s²

t = 4 s

Find: Δx and v

Δx = v₀ t + ½ at²

Δx = (0 m/s) (4 s) + ½ (3 m/s²) (4 s)²

Δx = 24 m

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6 0
2 years ago
1. Determine the image distance in each of the following.
miskamm [114]

It is given that for the convex lens,

Case 1.

u=−40cm

f=+15cm

Using lens formula

v

1

−

u

1

=

f

1

v

1

−

40

1

=

15

1

v

1

=

15

1

−

40

1

v=+24.3cm

The image in formed in this case at a distance of 24.3cm in left of lens.

Case 2.

A point source is placed in between the lens and the mirror at a distance of 40 cm from the lens i.e. the source is placed at the focus of mirror, then the rays after reflection becomes parallel for the lens such that

u=∞

f=15cm

Now, using mirror’s formula

v

1

+

u

1

=

f

1

v

1

+

∞

1

=

15

1

v=+15cm

The image is formed at a distance of 15cm in left of mirror

6 0
3 years ago
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