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topjm [15]
3 years ago
8

568 muons were counted by a detector on the top of Mount Washington in a one hour period of time. Assuming moving muons keep tim

e at the same rate as stationary muons, then 27 should survive until sea level. The fact that 412 muons were detected by the same equipment at sea level reveals that
A. the stationary clock measures time differently at different altitudes
B. the moving clocks keep time at the same rate as stationary clocks
C. that moving clocks run slower
D. that moving clocks run faster
Physics
2 answers:
AlladinOne [14]3 years ago
6 0
The answer to this question is:

C-"That moving clocks run slower"

Your Welcome :)
Cerrena [4.2K]3 years ago
4 0

Explanation:

The fact that 412 muons were detected by the same equipment at sea level reveals that moving clocks run slower. This is due to the reason of time dilation.

The time dilation slow down time with respect to external observer. The time dilation is caused due to the force of gravity and the velocity with which the object is moving.

Hence, the correct option is (c) "moving clocks run slower".

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A 500 kg block is attached to a horizontal spring that is at its equilibrium length, and whose force constant is 30 N/m. The blo
m_a_m_a [10]

Answer:

x = 0.396 m

Explanation:

The best way to solve this problem is to divide it into two parts: one for the clash of the putty with the block and another when the system (putty + block) compresses it is   spring

Data the putty has a mass m1 and velocity vo1, the block has a mass m2 .  t's start using the moment to find the system speed.

Let's form a system consisting of putty and block; For this system the forces during the crash are internal and the moment is preserved. Let's write the moment before the crash

    p₀ = m1 v₀₁

Moment after shock

    p_{f} = (m1 + m2) v_{f}

   p₀ = p_{f}

   m1 v₀₁ = (m1 + m2) v_{f}

  v_{f} = v₀₁ m1 / (m1 + m2)

   v_{f}= 4.4 600 / (600 + 500)

  v_{f} = 2.4 m / s

With this speed the putty + block system compresses the spring, let's use energy conservation for this second part, write the mechanical energy before and after compressing the spring

Before compressing the spring

   Em₀ = K = ½ (m1 + m2) v_{f}²

After compressing the spring

   E_{mf} = Ke = ½ k x²

As there is no rubbing the energy is conserved

   Em₀ = E_{mf}

   ½ (m1 + m2) v_{f}² = = ½ k x²

   x = v_{f} √ (k / (m1 + m2))

   x = 2.4 √ (11/3000)

   x = 0.396 m

7 0
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The answer is chemical energy

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That is more of a History of English question.

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A transformer is intended to decrease the value of the alternating current from 500 amperes to 25 amperes. The primary coil cont
EastWind [94]

Answer:

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Explanation:

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Current in secondary coil I_{S} = 25 A

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