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topjm [15]
3 years ago
8

568 muons were counted by a detector on the top of Mount Washington in a one hour period of time. Assuming moving muons keep tim

e at the same rate as stationary muons, then 27 should survive until sea level. The fact that 412 muons were detected by the same equipment at sea level reveals that
A. the stationary clock measures time differently at different altitudes
B. the moving clocks keep time at the same rate as stationary clocks
C. that moving clocks run slower
D. that moving clocks run faster
Physics
2 answers:
AlladinOne [14]3 years ago
6 0
The answer to this question is:

C-"That moving clocks run slower"

Your Welcome :)
Cerrena [4.2K]3 years ago
4 0

Explanation:

The fact that 412 muons were detected by the same equipment at sea level reveals that moving clocks run slower. This is due to the reason of time dilation.

The time dilation slow down time with respect to external observer. The time dilation is caused due to the force of gravity and the velocity with which the object is moving.

Hence, the correct option is (c) "moving clocks run slower".

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<em>C. the blue colour of the Earth's sky</em>

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8 0
3 years ago
4. Think back to Coulomb's Law. Two coins with identical charges are placed on a lab table 1.35 m apart.
FinnZ [79.3K]
A) To calculate the charge of each coin, we must apply the expression of the Coulomb's Law:
 
 F=K(q1xq2)/r²
 
 F: The magnitud of the force between the charges. (F=2.0 N).
 K: Constant of proporcionality of the Coulomb's Law (K=9x10^9 Nxm²/C²).
 q1 and q2: Electrical charges.
 r: The distance between the charges (r=1.35 m).
 
 We have the values of F, K and r, so we can calculate q1xq2, because both<span> coins have  identical charges:
</span> 
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 q1xq2=(1.35 m)²(2.0 N)/9x10^9 Nxm²/C²
 q1xq2=3x10^-10 C
 q1=q2=(<span>3x10^-10 C)/2
 
 </span>Then, the charge of each coin, is:
<span> 
 q1=1.5x</span><span>10^-10 C 
 
 </span>q2=1.5x10^-10 C

B) <span>Would the force be classified as a force of attraction or repulsion?
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