Answer:
The new volume will be 367mL
Explanation:
Using PV = nRT
V1 = 259mL = 0.000259L
n1 = 0.552moles
At constant temperature and pressure, the value is
P * 0.000259 = 0.552 * RT ------equation 1
= 0.552 / 0.000259
= 2131.274
V2 = ?
n2 = 0.552 + 0.232
n2 = 0.784mole
Using ideal gas equation,
PV = nRT
P * V2 = 0.784 * RT ---------- equation 2
Combining equations 1 and 2 we have;
V2 = 0.784 / 2131.274
V2 = 0.000367L
V2 = 367mL
Answer:
Two
Explanation:
I believe your unbalanced equation should be
H₂O₂ + I₂ ⟶ IO₃⁻
The half-reactions and the overall reaction are:
5 × [H₂O₂ + 2H⁺ +2e⁻ ⟶ 2H₂O]
1 × <u>[ I₂ + 6H₂O ⟶ 2IO₃⁻ + 12H⁺ + 10e⁻]
</u>
5H₂O₂ + I₂ ⟶ 2IO₃⁻ + 2H⁺ + 4H₂O
The reaction needs two hydrogen ions for balancing.
It should be 2+ because Ba is in the 2nd group which means it needs two more electrons.
<span>The law of sines can be solved when you know any two angles of a triangle and a side (AAS-case). The second case is when you know two sides and a non-included angle (SSA-case). Recall law of sines is Sin(A)/A = Sin(B)/B = Sin(C)/C .</span>
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