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3 years ago

2. a) Force affects the body and results in different changes. The grid given below

Physics

1 answer:

postnew [5]3 years ago

8 0

Answer:

Please find the answer in the explanation

Explanation:

Given that Force affects the body and results in different changes.

The grid that has the words related to the effects of force are :

a) Force could be a push or a pull.

c) Force has magnitude as well as direction.

e) Force acting on an object may cause a change in its state of motion or a change in its shape.

f) A force can act on an object with or without being in contact with it.

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murzikaleks [220]

The advertising method that this demonstrates is card stacking.

An advertising method in which the buyers are persuaded to buy a product by deliberately disguising information and trying to distort actual details by suppressing the holistic information on the product.

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This is a case of card stacking.

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7 0

2 years ago

A child of mass 46.2 kg sits on the edge of a merry-go-round with radius 1.9 m and moment of inertia 130.09 kg m2 . The merrygo-

Vedmedyk [2.9K]

Answer:

The angular velocity is $w_f = 4.503 \ rad/s$

Explanation:

From the question we are told that

The mass of the child is $m_c = 46.2 \ kg$

The radius of the merry go round is $r = 1.9 \ m$

The moment of inertia of the merry go round is $I_m = 130.09 \ kg \cdot m^2$

The angular velocity of the merry-go round is $w = 2.4 \ rad/s$

The position of the child from the center of the merry-go-round is $x = 0.779 \ m$

According to the law of angular momentum conservation

The initial angular momentum = final angular momentum

$L_i = L_f$

=> $I_i w_i = I_fw_f$

Now $I_i$ is the initial moment of inertia of the system which is mathematically represented as

$I_i = I_m + I_{b_1}$

Where $I_{b_i}$ is the initial moment of inertia of the boy which is mathematically evaluated as

$I_{b_i} = m_c * r$

substituting values

$I_{b_i} = 46.2 * 1.9^2$

$I_{b_i} = 166.8 \ kg \cdot m^2$

Thus

$I_i =130.09 + 166.8$

$I_i = 296.9 \ kg \cdot m^2$

Thus

$I_i * w_i =L_i= 296.9 * 2.4$

$L_i = 712.5 \ kg \cdot m^2/s$

Now

$I_f = I_m + I_{b_f }$

Where $I_{b_f}$ is the final moment of inertia of the boy which is mathematically evaluated as

$I_{b_f} = m_c * x$

substituting values

$I_{b_f} = 46.2 * 0.779^2$

$I_{b_f} = 28.03 kg \cdot m^2$

Thus

$I_f = 130.09 + 28.03$

$I_f = 158.12 \ kg \ m^2$

Thus

$L_f = 158.12 * w_f$

Hence

$712.5 = 158.12 * w_f$

$w_f = 4.503 \ rad/s$

8 0

3 years ago

In object of mass 30 kg is in freefall in a vacuum where there is no air resistance determine the acceleration of the object

Leto [7]

The free fall acceleration due to the Earth's gravity will always be 9.8m/s^2. So, if this question is taking place on Earth, then the acceleration of an object in free fall is 9.8m/^2.

3 0

3 years ago

The demand for your hand-made skateboards, in weekly sales, is q = −3p + 700 if the selling price is $p. You are prepared to sup

Y_Kistochka [10]

Answer:

you should sell your skateboards at $240

Explanation:

The price p to sell your skateboards for so that there is neither a shortage nor a surplus is the price that makes equal the quantity of sales and the quantity of supply, so p is equal to:

q (sales) = q (supply)

-3p + 700 = 2p - 500

700 + 500 = 2p + 3p

1200 = 5p

1200/5 = p

$240 = p

3 0

3 years ago

A constant force is exerted for a short time interval on a cart that is initially at rest on an air track. This force gives the

Ilya [14]

Answer:

d) is the same as when it started from rest

Explanation:

using equation of motion

v = u + at

second law of momentum defines

F = ma

a = F /m

the equation becomes

v = u + (F/m)t

from hear

since v is directly proportional to the force and the force remain the same, the increase in the cart speed will also remain the same.

5 0

4 years ago