Answer:
In a transverse wave, the particles are displayed perpendicular to the direction the wave travels . in a longitudinal wave the particles are are displayed parallel to the direction the wave travels. an example of longitudinal waves in compressions moving along a slinky.
Multiply field strength (N/kg) by mass (kg) to get weight (N)
At the start, the car is carrying
4.7 kg * (9.8 N/kg) = 46.06 N
of fuel.
At the end, it is carrying
3.0 kg * (9.8 N/kg) = 29.4 N.
Assuming the car remains completely intact, its weight was reduced by
46.06 N - 29.4 N = 16.66 N.
Answer:
v = 2.974
Explanation:
Perhaps the formula should be
v = √(2*g*d (sin(θ) - uk*cos(θ) ) This is a bit easier to read.
v = √(2* 9.80*0.725(0.707 - 0.12*0.707) ) Substitute values. Find 2*g*d
v = √14.21 * (0.707 - 0.0849) Figure out Sin(θ) - uk cos(θ)
v = √14.21 * (0.6222)
v = √8.8422 Take the square root of the value
v = 2.974
Q1. The answer is 8.788 m/s
V2 = V1 + at
V1 - the initial velocity
V2 - the final velocity
a - the acceleration
t - the time
We have:
V1 = 4.7 m/s
a = 0.73 m/s²
t = 5.6 s
V2 = ?
V2 = 4.7 + 0.73 * 5.6
V2 = 4.7 + 4.088
V2 = 8.788 m/s
Q2. The answer is 9.22 s
V2 = V1 + at
V1 - the initial velocity
V2 - the final velocity
a - the acceleration
t - the time
We have:
V2 = 0 (because it reaches a complete stop)
V1 = 4.7 m/s
a = -0.51 m/s²
t = ?
0 = 4.7 + (-0.51)*t
0 = 4.7 - 0.51t
0.51t = 4.7
t = 4.7 / 0.51
t = 9.22 s
