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3 years ago

What is a precipitate?

Physics

2 answers:

Lunna [17]3 years ago

7 0

Rain is considered a precipitate. Along with: drizzle, sleet, snow and hail.

hope this helps :)

oksian1 [2.3K]3 years ago

5 0

A precipitate is rain, but also known in chemistry as a <span>reaction that failed to react.</span>

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Apply a force of 50 N right to the box. Describe the motion of the box using physics terms (i.E. Velocity, acceleration, displac

Nikitich [7]

When unbalanced force is acting on the system of mass then as per Newton's II law we can say

$F_{net} = ma$

here we have

$a = \frac{F}{m}$

now since the force and mass both given to us so we can find acceleration of object from this

now when 50 N force is applied on a box then this 50 N force is unbalanced force on it and it will produce acceleration to the box

So here we can say that box will accelerate with constant acceleration and hence its velocity will linearly increase with time.

Now the displacement of the object will be given as

$d = v_i * t + \frac{1}{2} at^2$

so here the displacement will be a quadratic function of time and increases with time as well

so here overall the motion will be of constant acceleration, uniformly increasing velocity and displacement will be a quadratic function of time

4 0

3 years ago

Which element causes a star to go through a high mass cycle

denis23 [38]

Answer: As larger stars reach the red-giant phase, their temperature increases as helium is fused into carbon. Core temperature increases, with fusion forming oxygen, nitrogen and iron. When the star core converts to iron, fusion ceases.

Explanation:

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3 years ago

A car traveling in a straight line has a velocity of +4.4 m/s. after an acceleration of 0.65 m/s2 , the car's velocity is +8.3 m

nydimaria [60]

Answer:

1.53seconds

Explanation:

Using first equation of motion :

V=U + at

Where final velocity (V) =+8.3m/s

Initial velocity (U) =+4.4m/s

Acceleration (a) = 0.65m/s^2

time(s)=?

V=U + at

+8.3^2 = +4.4 + 0.65 * t

Making t the subject of the formula :

Therefore, t= ( +8.3 - 4.4)/0.65 = 1.53seconds

7 0

3 years ago

You place an ice cube of mass 7.50×10−3kg and temperature 0.00∘C on top of a copper cube of mass 0.220 kg. All of the ice melts,

g100num [7]

Answer:

$T = 29.66 ^o C$

Explanation:

As we know that here final equilibrium temperature is 0 degree C

so we can use energy conservation here

heat given by the cube = heat absorbed by the ice

so we have

$ms \Delta T = m' L$

so here we have

$0.220(385)(T - 0) = (7.50 \times 10^{-3})(3.35 \times 10^5)$

$T = \frac{2512.5}{0.220 \times 385}$

$T = 29.66 ^o C$

5 0

3 years ago

Examine the graph. Select the statement that best describes the energy change in the particles of a substance during melting.

serg [7]

Answer:

B) Absorbed energy results in the change in potential energy.

Explanation:

i got it wrong on usatestpreo

3 0

3 years ago

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