Answer:
Both erg and Joule are units of Energy in the CGS and S.I system respectively.
Joule and erg can also be written as (kg m2/s2) and (g cm2/s2) respectively.
Explanation:
1 Joule = 107 erg ⇒ 107 kg m2/s2.
Explanation:
Both distributions describe the number of times an event occurs in a givn number of trials. In the binomial distribution, the probability is the same for each trial. While in the hypergeometric distribution, each trial changes the probability of each subsequent trial, since there is no replacement.
Answer:
(a) 11.3 T
(b) 6.09 T
Explanation:
Current, I = 14 kA = 14000 A
number of turns, N = 900
inner radius, r = 0.7 m
outer radius, R = 1.3 m
The magnetic field due to a circular coil is given by

(a) The magnetic field due to the inner radius is

(b) The magnetic field due to the outer radius is

Answer:
17.54N in -x direction.
Explanation:
Amplitude (A) = 3.54m
Force constant (k) = 5N/m
Mass (m) = 2.13kg
Angular frequency ω = √(k/m)
ω = √(5/2.13)
ω = 1.53 rad/s
The force acting on the object F(t) = ?
F(t) = -mAω²cos(ωt)
F(t) = -2.13 * 3.54 * (1.53)² * cos (1.53 * 3.50)
F(t) = -17.65 * cos (5.355)
F(t) = -17.57N
The force is 17.57 in -x direction
Answer:
P₂ = 1.22 kPa
Explanation:
This problem can be solved using the equation of state:

where,
P₁ = initial pressure = 1 KPa
P₂ = final pressure = ?
V₁ = initial Volume = 1 liter
V₂ = final volume = 1.1 liter
T₁ = initial temperature = 290 k
T₂ = final temperature = 390 k
Therefore,

<u>P₂ = 1.22 kPa</u>