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romanna [79]
2 years ago
9

The low-_____ areas in a sound wave are called rarefactions. A. period B. frequency C. energy D. density

Physics
2 answers:
pashok25 [27]2 years ago
6 0

Answer:

Density

Explanation:

Apex

Delicious77 [7]2 years ago
4 0
You can picture a sound wave a lot like a Slinky wave . . . a
thicker, compressed blob moving along the path, with thinner,
stretched-out places before and after it.

The thicker parts of a sound wave, where the air is more dense,
are called compressions.

The thinner parts of a sound wave, where the air is less dense,
are called rarefactions.
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Which of these actions requires KINETIC Energy? Choose all of the correct answers.
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Answer:

turning a doorknob

Explanation:

it will snap back once you release it.

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2 years ago
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What type of energy is involved when a river moves sediment and erodes its banks?
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<span>First question: The type of energy involved when a river moves sediment and erodes its banks is: option d. Kinetic energy. Kinetic energy is the energy associated with motion. A body (in this case the water) that moves has an energy associated with its motion that is proportional to the speed (exactly to the square of the speed). When the water collides with the banks it is the kinetic energy of the river that erodes it Second question: the answer is the option d. As gravity pulls water down a slope potential energy changes to knietic energy. This is the, water loses altitude and gains velocity. The potential energy. which is proportional to the height, decreases and the kinetic energy, which is proportional to the square of the speed, increases.</span>
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3 years ago
A particle moves along the x axis so that its velocity at time t is given by v(t)=
vodomira [7]

Answer:

a = 0.7267 ,  acceleration is positive therefore the speed is increasing  

Explanation:

The definition of acceleration is

         a = dv / dt

they give us the function of speed

         v = - (t-1) sin (t² / 2)

         a = - sin (t²/2) -  (t-1) cos (t²/2)  2t / 2

         a = - sin (t²/2) - t (t-1)  cos (t²/2)

the acceleration for t = 4 s

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          a = -sin 8 - 12 cos 8

remember that the angles are in radians

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the problem does not indicate the units, but to be correct they must be m/s²

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The needle in the following diagram rotates around a fixed point in the middle. Based on the information given, what way will th
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3 years ago
A worker lifts a 20.0-kg bucket of concrete from the ground up to the top of a 25.0-m tall building. The bucket is initially at
yuradex [85]

Answer:

Minimum work = 5060 J

Explanation:

Given:

Mass of the bucket (m) = 20.0 kg

Initial speed of the bucket (u) = 0 m/s

Final speed of the bucket (v) = 4.0 m/s

Displacement of the bucket (h) = 25.0 m

Let 'W' be the work done by the worker in lifting the bucket.

So, we know from work-energy theorem that, work done by a force is equal to the change in the mechanical energy of the system.

Change in mechanical energy is equal to the sum of change in potential energy and kinetic energy. Therefore,

\Delta E=\Delta U+\Delta K\\\\\Delta E= mgh+\frac{1}{2}m(v^2-u^2)

Therefore, the work done by the worker in lifting the bucket is given as:

W=\Delta E\\\\W=mgh+\frac{1}{2}m(v^2-u^2)

Now, plug in the values given and solve for 'W'. This gives,

W=(20\ kg)(9.8\ m/s^2)(25\ m)+\frac{1}{2}(20\ kg)(4^2-0^2)\ m^2/s^2\\\\W=4900\ J +160\ J\\\\W=5060\ J

Therefore, the minimum work that the worker did in lifting the bucket is 5060 J.

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3 years ago
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