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ella [17]
4 years ago
12

The founder of Islam was _____. Abbas ibn Abd al-Muttalib Muhammad Abu Bakr Khosrau

Chemistry
2 answers:
Grace [21]4 years ago
5 0
The founder of Islam was Muhammad
-Corey
raketka [301]4 years ago
3 0
Muhammad was the founder of Islam
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The identity of an element depends on the number of protons and neutrons in the nucleus. protons in the atom. neutrons in the at
labwork [276]

Answer:

protons in the atom.

Explanation:

The identity of an element relies on the number of protons in its atom. This is called the atomic number. The atomic number is the basis of the periodic table of elements. Modern periodic law states that "the properties of elements are a periodic function of their atomic number".

Atomic number of atoms do not change and they are convieniently used in identifying an atom.

8 0
3 years ago
How many atoms of carbon or one mole of glucose
professor190 [17]

Answer:

6 carbon atoms

Explanation:

For instance, we can say that one molecule of glucose has 6 carbon atoms, or we can say, equivalently, that one mole of glucose has 6 moles of carbon atoms

3 0
3 years ago
1. Based on the information from the movie, what can you conclude about the most common chemical compound on earth?
Sliva [168]

Answer:

1.   d. It's water

2.  a. It does not always retain the properties of the substances that make it up

Explanation:

6 0
3 years ago
How many significant figures are in the following measurement? 433.8 liters
motikmotik
4 significant figures
3 0
3 years ago
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When NH3(g) reacts with O2(g), the products of the combustion are NO(g) and H2O(g). What volume of O2(g) is required to react wi
arlik [135]

<u>Answer:</u> The volume of oxygen gas required is 3.75 mL

<u>Explanation:</u>

STP conditions:

1 mole of a gas occupies 22.4 L of volume.

We are given:

Volume of ammonia reacted = 3.00 mL = 0.003 L    (Conversion factor:  1 L = 1000 mL)

The chemical equation for the reaction of ammonia with oxygen follows:

4NH_3(g)+5O_2\rightarrow 4NO(g)+6H_2O(g)

By Stoichiometry of the reaction:

(4 × 22.4) L of ammonia reacts with (5 × 22.4) L of oxygen gas

So, 0.003 L of ammonia will react with = \frac{(5\times 22.4)}{(4\times 22.4)}\times 0.003=0.00375L=3.75mL of oxygen gas

Hence, the volume of oxygen gas required is 3.75 mL

4 0
3 years ago
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