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natita [175]
3 years ago
14

What type of chemical reaction is NH3

Chemistry
1 answer:
Gekata [30.6K]3 years ago
7 0

Answer:

Combination reaction

Explanation:

N2+H2 = NH3

they combine together to form a product

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The compound KOH is called
denis-greek [22]

Answer:

It is called Potassium Hydroxide

4 0
3 years ago
Read 2 more answers
A piece of unknown metal weighs 348g. When the metal piece absorbs 6.64kj of heat , its temperature increases from 24.4C to 43.6
Morgarella [4.7K]

Answer:

This metal could be the aluminium with a specific heat of H = 993 \frac{J}{kgC}

Explanation:

A pie of unknown metal presents a mass (M) of 348 g. This metal is heated using energy (E) of 6.64 kJ and the temperature increases from T1 =24.4 to T2 =43.6°C. We can calculate the specific heat (H) of this metal as follows

H = \frac{E}{M*(T2-T1)}

We can replace previously presented data in this equation. After simplifying and converting to adequated units, we found that

H = \frac{6640 J}{0.348 Kg*(43.6-24.4) C} =\frac{6640 J}{6.686 KgC}

Finally, the specific heat of this metal is

H = 993 \frac{J}{kgC}

The aluminium could be the metal, its specific heat is similar to that found in this problem.

Finally,  we can conclude that this metal could be the aluminium with a specific heat of H = 993 \frac{J}{kgC}

7 0
3 years ago
How many gallons of water in lake lewisville?
Vlada [557]
1.422 × 10^11 us liquid gallons
5 0
2 years ago
A 32.4 L gas sample at STP is compressed to a volume of 28.4 L, and the temperature is increased to 352 K. What is the new press
Sindrei [870]

Answer:

1.47 atm

Explanation:

Step 1: Given data

  • Initial volume (V₁): 32.4 L
  • Initial pressure (P₁): 1 atm (standard pressure)
  • Initial temperature (T₁): 273 K (standard temperature)
  • Final volume (V₂): 28.4 L
  • Final pressure (P₂): ?
  • Final temperature (T₂): 352 K

Step 2: Calculate the final pressure of the gas

We can calculate the final pressure of the gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

P₂ = P₁ × V₁ × T₂ / T₁ × V₂

P₂ = 1 atm × 32.4 L × 352 K / 273 K × 28.4 L = 1.47 atm

7 0
3 years ago
At a festival, spherical balloons with a radius of 280. Cm are to be inflated with hot air and released. The air at the festival
evablogger [386]

Answer:

8608.18 balloons

Explanation:

Hello! Let's solve this!

Data needed:

Enthalpy of propane formation: 103.85kJ / mol

Specific heat capacity of air: 1.009J · g ° C

Density of air at 100 ° C: 0.946kg / m3

Density of propane at 100 ° C: 1.440kg / m3

First we will calculate the propane heat (C3H8)

3000g * (1mol / 44g) * (103.85kJ / mol) * (1000J / 1kJ) = 7.08068 * 10 ^ 6 J

Then we can calculate the mass of the air with the heat formula

Q = mc delta T

m = Q / c delta T = (7.08068 * 10 ^ 6 J) / (1.009J / kg ° C * (100-25) ° C) =

m = 93566.96kg

We now calculate the volume of a balloon.

V = 4/3 * pi * r ^ 3 = 4/3 * 3.14 * 1.4m ^ 3 = 11.49m ^ 3

Now we calculate the mass of the balloon

mg = 0.946kg / m3 * 11.49m ^ 3 = 10.87kg

The amount of balloons is

93566.96kg / 10.87kg = 8608.18 balloons

5 0
3 years ago
Read 2 more answers
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