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Pachacha [2.7K]
3 years ago
13

How many moles of pcl3 contain 3.68 × 1025 chlorine atoms?

Chemistry
2 answers:
disa [49]3 years ago
4 0
To answer the question above, we take note first that every mole of PCl₃ contains 3 atoms of Cl. First, we divide the given number by 3.
                                   3.68 x 10²⁵ / 3 = 1.227 x 10²⁵ 
Then, we divide the answer by the Avogadro's number which is equal to 6.022 x 10²³. That is,
                                    1.227 x 10²⁵ / (6.022 x 10²³) = 20.37
Thus, there are 20.37 mol of PCl₃. 
ch4aika [34]3 years ago
3 0

<u>Answer:</u> The moles of PCl_3 that contain given number of chlorine atoms is 20.4 moles

<u>Explanation:</u>

We are given:

Number of atoms of chlorine = 3.68\times 10^{25}

A chemical compound having chemical formula PCl_3

In 1 mole of phosphorus trichloride, 1 mole of phosphorus atom and 3 moles of chlorine atoms are present.

According to mole concept:

6.022\times 10^{23} number of molecules occupy 1 mole of a compound.

So, 3\times 6.022\times 10^{23}=1.8066\times 10^{24} number of chlorine atoms occupy 1 mole of phosphorus trichloride

Then, 3.68\times 10^{25} number of chlorine atoms will occupy = \frac{1}{1.8066\times 10^{24}}\times 3.68\times 10^{25}=20.4moles of phosphorus trichloride

Hence, the moles of PCl_3 that contain given number of chlorine atoms is 20.4 moles

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