Question

The area of a triangle is 15x^4+3x^3+4x^2-x-3 square meters. The length of the base of the triangle is 6x^2-2 meters. What is the height of the triangle?

Answer 1

Answer:

The height of the triangle is: $H = (5x^2 + x +3)$

Step-by-step explanation:

Here, the area the triangle  is given as: $15x^4 + 3x^3 + 4x^2 - x - 3$

Also, base of the triangle  = $(6x^2 -2)$

Let us assume the height of the triangle = H units

Now, AREA of TRIANGLE =  $\frac{1}{2} \times B \times H$

$\implies (15x^4+3x^3+4x^2-x-3 ) = \frac{1}{2} \times ( 6x^2-2) \times H\\\implies H =\frac{ (15x^4+3x^3+4x^2-x-3 )}{(3x^2-1)}$

Solving by LONG DIVISION, we get:

$H = (5x^2 + x +3)$

Hence, the height of the triangle is: $H = (5x^2 + x +3)$