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notka56 [123]
2 years ago
9

Consider the speed of light in another universe to be only 100 m/s. Two cars are traveling along a highway in opposite direction

s. Person 1 is travelling with speed of 39 m/s, and person 2 is travelling in opposite direction with speed of 31 m/s. How fast does person 1 measure person 2 to be traveling? How fast does person 2 measure person 1 to be traveling?
Physics
1 answer:
olganol [36]2 years ago
8 0

Answer:

-62.45m/s and +62.45m/s

Explanation:

The formula for relativistic speed

This is the speed of A with respect to B

V_{AB}=\frac{V_{A}-V_{B}}{1-\frac{V_{A}V_{B}}{C^2} }

where

V_{A} will be the velocity of person 1: 39m/s

V_{B} will be the velocity of person 2: -31m/s (negative because is travelling in opposite direction)

and C the velocity of light: 100m/s

The velocity of person 1 measured by person 2 is:

V_{AB}=\frac{39m/s-(-31m/s)}{1-\frac{(39m/s)(-31m/s)}{(100m/s)^2}}=62.45m/s

The velocity of person 2 measured by person 1 is:

V_{BA}=\frac{V_{B}-V_{A}}{1-\frac{V_{B}V_{A}}{C^2} }

V_{BA}=\frac{-31m/s-39m/s}{1-\frac{(-31m/s)(39m/s)}{(100)^2} }=-62.45m/s

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