Answer:
Explanation:
Given that, .
Pressure around scuba is
P = 10^5 Pa
1 Pa = 1 N/m²
Then
P = 10^5 N/m²
Descending height
h = 10m
Change in force per unit square centimetre
We know that,
Pressure = Force / Area
Then,
Force / Area is the required question we are finding
Then,
Force / Area = 10^5 N / m²
So, let convert the m² to cm²
100cm = 1m
(100cm)² = (1m)²
10⁴cm² = 1m²
Then,
Force / Area = 10^5 N/m² × 1m² / 10⁴cm²
Force / Area = 10 N/cm²
So, the force per unit square centimeters is 10.
I’m sorry i haven’t found the answer to this
4 N/cm^2 is the answer. the way you get this is the formula for pressure is P=F/A. So you would plug in the numbers which would make the equation P=12/3 which you know equals 4. The units for pressure is N/cm^2 or N/m^2
I hope this helps
(a) The work done by the applied force is 26.65 J.
(b) The work done by the normal force exerted by the table is 0.
(c) The work done by the force of gravity is 0.
(d) The work done by the net force on the block is 26.65 J.
<h3>
Work done by the applied force</h3>
W = Fdcosθ
W = 14 x 2.1 x cos25
W = 26.65 J
<h3>
Work done by the normal force</h3>
W = Fₙd
W = mg cosθ x d
W = (2.5 x 9.8) x cos(90) x 2.1
W = 0 J
<h3>Work done force of gravity</h3>
The work done by force of gravity is also zero, since the weight is at 90⁰ to the displacement.
<h3> Work done by the net force on the block</h3>
∑W = 0 + 26.65 J = 26.65 J
Thus, the work done by the applied force is 26.65 J.
The work done by the normal force exerted by the table is 0.
The work done by the force of gravity is 0.
The work done by the net force on the block is 26.65 J.
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It increases confidence because the more times you conduct the same experiment over and over should either prove your hypothesis right and wrong and eliminate any random occurrences that might affect your results.