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3 years ago

How many atoms are there in 144g of sucrose, C12H22O11 or sugar molecules?

Chemistry

1 answer:

kati45 [8]3 years ago

8 0

Answer:

2.53×10²³ atoms

Explanation:

To solve this, convert grams to moles and moles to atoms.

To convert grams to moles, use the molar mass of C₁₂H₂₂O₁₁ (342.296 g/mol). Divide the mass by the molar mass to get moles. Moles = 0.4207

To convert moles to atoms, use Avogadro's number (6.022×10²³ atoms/mol). Multiply moles by Avogadro's number to get atoms. Atoms = 2.53×10²³

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The concentration of Rn−222 in the basement of a house is 1.45 × 10−6 mol/L. Assume the air remains static and calculate the con

bonufazy [111]

Answer: The concentration of radon after the given time is $3.83\times 10^{-30}mol/L$

Explanation:

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

We are given:

$t_{1/2}=3.82days$

Putting values in above equation, we get:

$k=\frac{0.693}{3.82}=0.181days^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $0.181days^{-1}$

t = time taken for decay process = 3.00 days

$[A_o]$ = initial amount of the reactant = $1.45\times 10^{-6}mol/L$

[A] = amount left after decay process = ?

Putting values in above equation, we get:

$0.181days^{-1}=\frac{2.303}{3.00days}\log\frac{1.45\times 10^{-6}}{[A]}$

$[A]=3.83\times 10^{-30}mol/L$

Hence, the concentration of radon after the given time is $3.83\times 10^{-30}mol/L$

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4 years ago

Chemistry Help! Reasons why nonmetals form covalent bonds?

melisa1 [442]

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3 years ago

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Will a double replacement reaction occur if a potassium hydroxide solution is mixed with a lead(II) nitrate solution? Briefly ex

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3 years ago

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Determine the percent yield of a reaction that produces 28.65 g of Fe when 50.00 g of Fe2O3 react with excess Al according to th

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Answer:

The percent yield of the reaction is 82%

Explanation:

First step: make the chemist equation.

2 Al (s) + Fe2O3 (s) → 2 Fe (s) + Al2O3 (s)

As the statement says that aluminun is in excess, the limiting reactant is the Fe2O3

Second step: Find out the moles in the reactant.

Molar weight Fe2O3: 159.7 g/m

Mass / Molar weight = moles

50 g /159.7 g/m = 0.313 moles

Third step: Analyse the reaction. 1 mol of Fe2O3 makes 2 moles of Fe.

1 mol Fe2O3 ____ 2Fe

0.313 mol Fe2O3 ____ 0.626 moles

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Moles . molar weight = mass

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This will be the 100% yield of the reaction but we only made 28.65 g

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28.65 g ____ 82.09 %

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4 years ago

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