1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NeX [460]
3 years ago
5

Write the following in standard notation: 2.8 x 10-5s.

Chemistry
1 answer:
GaryK [48]3 years ago
5 0

Answer:

2.8 X 10-5s in standard notation is 28-5s

Explanation:

Multiply 2.8 by 10

You might be interested in
A piece of iron is heated to 120'C then placed in a calorimeter containing 50g of water. The water temperature is raised from 30
Lana71 [14]

Answer:

Mass of iron = 59.375 gm

Explanation:

Calories ( or joules) are added to the water by the hot steel so at the endpoint they are BOTH at 40 C

 The water gains:

     4.18  j/g-C  * 50 * (40-30 C) = 2090 j

The steel gave up 2090 j going from 120 to 40 C

2090 = .44 j/g-C  * m * (120-40)    solve fro m = 59.375 gm

3 0
2 years ago
The reaction of ammonia and hydrogen chloride gas:
oee [108]
It's replacement reaction. Hope it helped
8 0
3 years ago
Energy leaves the sun as light from region called the?
tino4ka555 [31]
Late answer:
Chromosphere.
4 0
3 years ago
The solubility of water in diethyl ether has been reported to be 1.468 % by mass.' Assuming that 23.0 mL of diethyl ether were a
melomori [17]

Explanation:

As it is given that solubility of water in diethyl ether is 1.468 %. This means that in 100 ml saturated solution water present is 1.468 ml.

Hence, amount of diethyl ether present will be calculated as follows.

                          (100ml - 1.468 ml)

                        = 98.532 ml

So, it means that 98.532 ml of diethyl ether can dissolve 1.468 ml of water.

Hence, 23 ml of diethyl ether can dissolve the amount of water will be calculated as follows.

          Amount of water = \frac{1.468 ml \times 23 ml}{98.532 ml}

                                       = 0.3427 ml

Now, when magnesium dissolves in water then the reaction will be as follows.

                Mg + H_{2}O \rightarrow Mg(OH)_{2}

Molar mass of Mg = 24.305 g

Molar mass of H_{2}O = 18 g

Therefore, amount of magnesium present in 0.3427 ml of water is calculated as follows.

           Amount of Mg = \frac{24.305 g \times 0.3427 ml}{18 g}  

                                    = 0.462 g

   

6 0
3 years ago
What is refraction? * Bending of light<br> Reflection of light
sdas [7]
Refraction is the bending of light (it also happens with sound, water and other waves) as it passes from one transparent substance into another. This bending by refraction makes it possible for us to have lenses, magnifying glasses, prisms and rainbows. Even our eyes depend upon this bending of light. Hope this helps!
6 0
3 years ago
Read 2 more answers
Other questions:
  • 6. 30.0 g of each of the following acids are needed. Find the volume of each that must be measured out in a graduated cylinder.
    13·2 answers
  • in what ways does solar energy help or harm the enviornment? give a couple of examples. if it hurts the evironment, explain how
    10·1 answer
  • Complete the Lewis structure of the molecule. Draw the missing dots and dashes representing the valence electrons in the molecul
    15·2 answers
  • Determine the empirical formula for c6n4o10
    11·1 answer
  • The following chemical equation is unbalanced. When the equation is balanced, what is the coefficient for pure calcium (Ca)? A.
    9·2 answers
  • Non-metal atoms can form:
    10·2 answers
  • Describes what occurs in facilitated diffusion?
    12·1 answer
  • A sample of an unknown substance has a mass of 0.465 kg. If 3,000.0 J of heat is required to heat the substance from 50.0°C to 1
    12·2 answers
  • A piston compresses the air in the cylinder by doing 67.0 J of work on the air. As a result, the air gives off 149.0 J of heat t
    8·1 answer
  • Plss answer!!! I need help fast
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!