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NeX [460]
3 years ago
5

Write the following in standard notation: 2.8 x 10-5s.

Chemistry
1 answer:
GaryK [48]3 years ago
5 0

Answer:

2.8 X 10-5s in standard notation is 28-5s

Explanation:

Multiply 2.8 by 10

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Zigmanuir [339]
By using chromatography
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3 years ago
What is a sign that a chemical change has occurred?
blondinia [14]

Answer:

The production of heat, light, or smoke is observed.

3 0
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Read 2 more answers
How many grams of sodium acetate are in solution in the third beaker?
Kipish [7]

Answer:

46g of sodium acetate.

Explanation:

The data is: <em>Precipitation from a supersaturated sodium acetate solution. The solution on the left was formed by dissolving 156g of the salt in 100 mL of water at 100°C and then slowly cooling it to 20°C. Because the solubility of sodium acetate in water at 20°C is 46g per 100mL of water, the solution is supersaturated. Addition of a sodium acetate crystal causes the excess solute to crystallize from solution.</em>

The third solution is the result of the equilibrium in the solution at 20°C. As the maximum quantity that water can dissolve of sodium acetate at this temperature is 46g per 100mL and the solution has 100mL <em>there are 46g of sodium acetate in solution. </em>The other sodium acetate precipitate because of decreasing of temperature.

I hope it helps!

6 0
3 years ago
How many significant figures are in the number 0.00230? O 6
EleoNora [17]

Answer:

0.00230 = <u>3 significant figures</u>

Explanation:

Significant digits or figures of a given number are the digits or figures that have meaning and contributes to the precision of the given number.        

Therefore, <u>0.00230 = 3 significant figures.</u>

Reason: The non-zeros figures and the trailing zero after the decimal are significant. Whereas, all the leading zeros are not considered significant.

4 0
3 years ago
How much heat (in Joules) is needed to raise the temperature of 257g of ethanol (cethanol=2.4 J/g°C) by 49.1°C?
Sonbull [250]

Answer:

Q = 30284.88 j

Explanation:

Given data:

Mass of ethanol = 257 g

Cp = 2.4 j/g.°C

Chnage in temperature = ΔT = 49.1°C

Heat required = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Now we will put the values in formula.

Q = 257 g× 2.4 j/g.°C × 49.1 °C

Q = 30284.88 j

8 0
3 years ago
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