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mario62 [17]
3 years ago
5

DVDs and Blu-ray disks store information in patterns that are read by laser light. The shorter the wavelength of the light, the

closer the data tracks can be placed on the disk.Part AA Blu-ray player uses violet light; a DVD player uses red light. Which disk can store more information?Drag the terms on the left to the appropriate blanks on the right to complete the sentences.Terms:DVDVioletRedBlu-ray Disk400nm700nmSentences to fill in:The wavelength of red light is around BLANK, whereas the wavelength of violet light is around BLANK. Since BLANK light has a smaller wavelength the data tracks on a BLANK can be spaced closer together and the BLANK can store more information.
Physics
2 answers:
Ilya [14]3 years ago
8 0

Answer: The Bluray Disk can store more information.

Answers for blank spaces are:

1) 700nm

2) 400nm

3) violet light

4) Blu-ray Disk

5) Blueray Disk

Explanation: violet light has a shorter wavelenght than red light. Since the disk that uses light with shorter wave can have their data more closely packed, then the Bluray will store more information per surface area.

Tju [1.3M]3 years ago
7 0

Answer: The Bluray Disk can store more information

The wavelenght of red light is around 700nm, whereas the wavelenght of violet light is around 400nm. Since the violet light has smaller wavelenght the data tracks on a Blu-ray Disk can be spaced closer together and the Blueray Disk can store more information

Explanation: Because a disk work by storing data using bits, the more bits can be stored in one place improves the total storage on the unit. The less the space to storage the bit, the more space overall for the disk.

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Pressure in a liquid increases with its ..........​
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An electron with a charge of -1.6 × 10-19 coulombs experiences a field of 1.4 × 105 newtons/coulomb. What is the magnitude of th
neonofarm [45]

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Explanation:

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We need to find the magnitude of the electric force on this electron due to this field. The electric force is given by :

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6 0
3 years ago
n a car lift used in a service station, compressed air exerts a force on a small piston that has a circular cross section of rad
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Answer: 1477.78 N

Explanation:

Let's assume that the cross sectional area of the smaller piston be A1

let's also assume the cross sectional area of the larger piston be A2

We assume the force applied to the smaller piston be F1

We also assume the force applied to the larger piston be F2

we then use the formula

F1/A1 = F2/A2

From our question,

The radius of the smaller piston is 5 cm = 0.05 m

The radius of the larger piston is 15 cm = 0.15 m

The force of the larger piston is 13300 N

The force of the smaller piston is unknown = F

A1 = πr² = 3.142 * 0.05² = 0.007855 m²

A2 = πr² = 3.142 * 0.15² = 0.070695 m²

F1/0.007855 = 13300/0.070695

F1 = (13300 * 0.007855) / 0.070695

F1 = 104.4715 / 0.070695

F1 = 1477.78 N

Thus, the force the compressed air must exert is 1477.78 N

5 0
3 years ago
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