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mario62 [17]
3 years ago
5

DVDs and Blu-ray disks store information in patterns that are read by laser light. The shorter the wavelength of the light, the

closer the data tracks can be placed on the disk.Part AA Blu-ray player uses violet light; a DVD player uses red light. Which disk can store more information?Drag the terms on the left to the appropriate blanks on the right to complete the sentences.Terms:DVDVioletRedBlu-ray Disk400nm700nmSentences to fill in:The wavelength of red light is around BLANK, whereas the wavelength of violet light is around BLANK. Since BLANK light has a smaller wavelength the data tracks on a BLANK can be spaced closer together and the BLANK can store more information.
Physics
2 answers:
Ilya [14]3 years ago
8 0

Answer: The Bluray Disk can store more information.

Answers for blank spaces are:

1) 700nm

2) 400nm

3) violet light

4) Blu-ray Disk

5) Blueray Disk

Explanation: violet light has a shorter wavelenght than red light. Since the disk that uses light with shorter wave can have their data more closely packed, then the Bluray will store more information per surface area.

Tju [1.3M]3 years ago
7 0

Answer: The Bluray Disk can store more information

The wavelenght of red light is around 700nm, whereas the wavelenght of violet light is around 400nm. Since the violet light has smaller wavelenght the data tracks on a Blu-ray Disk can be spaced closer together and the Blueray Disk can store more information

Explanation: Because a disk work by storing data using bits, the more bits can be stored in one place improves the total storage on the unit. The less the space to storage the bit, the more space overall for the disk.

You might be interested in
Gravity does not actually "pull" objects at
Radda [10]
I believe it’s (D. Any object)
5 0
3 years ago
A playground slide is in the form of an arc of a circle with a maximum height of 3.0 m, with a radius of 8.5 m, and with the gro
julia-pushkina [17]

Answer:

a) s \approx 6.676\,m

Explanation:

a) Let assume that the ground is not inclined, since the bottom of the playground slide is tangent to ground. Then, the length of given by the definition of a circular arc:

s = \frac{\pi}{4}\cdot R

s=\frac{\pi}{4}\cdot (8.5\,m)

s \approx 6.676\,m

The bottom of the slide has a height of zero. The physical phenomenon around Dr. Ritchey's daughter is modelled after Principle of Energy Conservation. The child begins at rest:

U_{g,A} = K_{B} + W_{fr}

m\cdot g \cdot h_{A} = \frac{1}{2}\cdot m \cdot v_{B}^{2} + f\cdot s

The average frictional force is cleared within the expression:

f = \frac{m\cdot (g\cdot h_{A}-\frac{1}{2}\cdot v_{B}^{2})}{s}

f = \frac{(12\,kg)\cdot [(9.807\,\frac{m}{s^{2}} )\cdot (3\,m)-\frac{1}{2}\cdot (4.5\,\frac{m}{s} )^{2} ]}{6.676\,m}

f = 34.684\,N

4 0
3 years ago
A<br> B <br> C <br> D<br><br> Plz help me.
Montano1993 [528]

Answer:

The correct option is;

{}               Man doing most work   {}    Box gaining the most energy

D   {}                 Y                                          Q

Explanation:

The given parameters of the question are;

The distance the box P is pushed by the Man X = 0

The force the Man X applies to the box P = x N

The distance the box Q is lifted by the Man Y = h > 0 meters

The minimum force the Man Y applies to the box Q = W, the weight of the box

Work done = Force × Distance

Energy gained = Potential energy + Kinetic Energy = (Mass × Gravity × Height = Weight × Height  = W × h) + 1/2 × Mass × Velocity²

The final velocity of either box = 0 m/s (The boxes are at rest on the ground or the shelf)

Therefore, Kinetic energy = 0 J

The work done by Man X = 0 × x = 0 J

The energy gained by the box P = W × 0 = 0 J

The work done by Man Y = W × h = W·h J

The energy gained by the box P = W × h = W·h J

We have, the work done by the man Y = W·h J is more than the work done by the man X = 0 J

The energy gained by the box P = W·h J is more than the energy gained by the box Q = 0 J

Therefore, the correct option is D, Man doing the most work is Y, box gaining the most energy is Q.

8 0
2 years ago
If 8000 C of charge pass through a section of wire in 2 minutes, what would the current be?
mars1129 [50]

Answer:

we know that current = charge/time

Explanation:

therefore,

A = 8000/120

A => 66.666.... amperes

8 0
3 years ago
What must be the units for the gravitational constant G in order for gravitational force to have units of newtons?
babunello [35]

Answer:

m³/(kg⋅s²)

Explanation:

Hello.

In this case, since the involved formula is:

F=G*\frac{m_1m_2}{r^2}

By writing a dimensional analysis with the proper algebra handling, we obtain:

N[=]G*\frac{kg*kg}{m^2}\\ \\kg*\frac{m}{s^2}[=]G *\frac{kg*kg}{m^2}\\\\G[=]\frac{kg*m*m^2}{kg^2*s^2}\\ \\G[=]\frac{m^3}{kg*s^2}

Thus, answer is:

m³/(kg⋅s²)

Note that the [=] is used to indicate the units of G.

Best regards

4 0
3 years ago
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