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mario62 [17]
3 years ago
5

DVDs and Blu-ray disks store information in patterns that are read by laser light. The shorter the wavelength of the light, the

closer the data tracks can be placed on the disk.Part AA Blu-ray player uses violet light; a DVD player uses red light. Which disk can store more information?Drag the terms on the left to the appropriate blanks on the right to complete the sentences.Terms:DVDVioletRedBlu-ray Disk400nm700nmSentences to fill in:The wavelength of red light is around BLANK, whereas the wavelength of violet light is around BLANK. Since BLANK light has a smaller wavelength the data tracks on a BLANK can be spaced closer together and the BLANK can store more information.
Physics
2 answers:
Ilya [14]3 years ago
8 0

Answer: The Bluray Disk can store more information.

Answers for blank spaces are:

1) 700nm

2) 400nm

3) violet light

4) Blu-ray Disk

5) Blueray Disk

Explanation: violet light has a shorter wavelenght than red light. Since the disk that uses light with shorter wave can have their data more closely packed, then the Bluray will store more information per surface area.

Tju [1.3M]3 years ago
7 0

Answer: The Bluray Disk can store more information

The wavelenght of red light is around 700nm, whereas the wavelenght of violet light is around 400nm. Since the violet light has smaller wavelenght the data tracks on a Blu-ray Disk can be spaced closer together and the Blueray Disk can store more information

Explanation: Because a disk work by storing data using bits, the more bits can be stored in one place improves the total storage on the unit. The less the space to storage the bit, the more space overall for the disk.

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According to Ohm's law, a circuit with a high resistance _____. will have a low electric current will have a high electric curre
lyudmila [28]
Remark
When you are asked a question like this, the first thing to do is search out a formula and put some limits on it.

Formula
I = E/R which comes from E = IR. To get to the derived formula, divide both sides by R
E/R = I*R/R
E/R = I

Discussion
This is an inverse relationship. That means that as one goes up the other one will go down. 

So in this case you keep E constant and you manipulate R and look at your results for I

Case 1

Let us say that E = 10 volts
Let us also say the R = 10 ohms

I = E/R
I = 10/10
I = 1 ohm

Case Two
Let's raise the Resistance to 100 ohms
E = 10
R = 100
I = 10/100 = 0.1 

Conclusion
As the Resistance goes up, the current goes down. Answer: A
8 0
3 years ago
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A protostar is _____.
defon

<u>Answer</u>

5.the stage before a star becomes a main sequence star

<u>Explanation</u>

A protostar is a small star that is still gathering its masses. When it forms enough masses it make a parent molecular cloud.

This been the case, from the choices given, the correct statement about a protostar is;

5.the stage before a star becomes a main sequence star

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3 years ago
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A 45 kg bear slides, from rest, 11 m down a lodgepole pine tree, moving with a speed of 5.8 m/s just before hitting the ground.
Viefleur [7K]

Answer:

Explanation:

a )

change  in the gravitational potential energy of the bear-Earth system during the slide  = mgh

= 45 x 9.8 x 11

= 4851 J

b )

kinetic energy of bear just before hitting the ground

= 1/2 m v²

= .5 x 45 x 5.8²

= 756.9 J

c ) If  the average frictional force that acts on the sliding bear be F

negative work done by friction

= F x 11 J

then ,

4851 J -  F x 11 =  756.9 J

F x 11 = 4851 J -   756.9 J

= 4094.1 J

F = 4094.1 / 11

= 372.2 N  

4 0
3 years ago
Two light bulbs have resistances of 400 Ω and 800 ΩThe two light bulbs are connected in series across a 120- V line. Find the cu
Natasha2012 [34]

1) Current in each bulb: 0.1 A

The two light bulbs are connected in series, this means that their equivalent resistance is just the sum of the two resistances:

R_{eq}=R_1 + R_2 = 400 \Omega + 800 \Omega=1200 \Omega

And so, the current through the circuit is (using Ohm's law):

I=\frac{V}{R_{eq}}=\frac{120 V}{1200 \Omega}=0.1 A

And since the two bulbs are connected in series, the current through each bulb is the same.

2) 4 W and 8 W

The power dissipated by each bulb is given by the formula:

P=I^2 R

where I is the current and R is the resistance.

For the first bulb:

P_1 = (0.1 A)^2 (400 \Omega)=4 W

For the second bulb:

P_1 = (0.1 A)^2 (800 \Omega)=8 W

3) 12 W

The total power dissipated in both bulbs is simply the sum of the power dissipated by each bulb, so:

P_{tot} = P_1 + P_2 = 4 W + 8 W=12 W

3 0
3 years ago
An astronaut on a space walk floats a little too far away
Lady bird [3.3K]

Answer:

He can throw it away from himself.

Explanation:

Newtons Third Law says that everything has an equal, yet opposite reaction on other objects.

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2 years ago
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