Answer:
A) About 
newtons
B) 76.518 newtons
C) 111.834 newtons
Explanation:
A) 
, where G is the universal gravitational constant, M 1 and 2 are the masses of both objects in kilograms, and r is the radius in meters. Plugging in the given numbers, you get:
B) You can find the weight of each object on Earth because you know the approximate acceleration due to gravity is 9.81m/s^2. Multiplying this by the mass of each object, you get a weight for the first particle of 76.518 newtons.
C) You can do a similar thing to the previous particle and find that its weight is 11.4*9.81=111.834 newtons.
Hope this helps!
Answer:
the quality of the refrigerant exiting the expansion valve is 0.2337 = 23.37 %
Explanation:
given data
pressure p1 = 1.4 MPa = 14 bar
temperature t1 = 32°C
exit pressure = 0.08 MPa = 0.8 bar
to find out
the quality of the refrigerant exiting the expansion valve
solution
we know here refrigerant undergoes at throtting process so
h1 = h2
so by table A 14 at p1 = 14 bar
t1 ≤ Tsat
so we use equation here that is
h1 = hf(t1) = 332.17 kJ/kg
this value we get from table A13
so as h1 = h2
h1 = h(f2) + x(2) * h(fg2)
so
exit quality = 
exit quality = 
so exit quality = 0.2337 = 23.37 %
the quality of the refrigerant exiting the expansion valve is 0.2337 = 23.37 %
Answer:
0.00695 A
Explanation:
µ represents 
. Multiply this by 6,950.
Answer:
1) Airman (AMN)
2) Airman First class (A1C)
3) Senior Airman (SrA)
4) Staff sergeant (SSgt)
5) Tech. Sergeant (TSgt)
6) Master sergeant (MSgt)
7) First sergeant (E-7)
8) Senior Master Sergeant (SMSgt)
9) First Sergeant (E-8)
10) Chief Master Sergeant (CMSgt)
11) First sergeant (E-9
12) Command chief Master Sergeant (CCM)
13) Chief Master Sergeant Of The Airforce (CMSAF
The specific heats of gases are given as Cp and Cv at constant pressure and constant volume respectively while solids and liquids are having only single value for specific heat.
