Answer:

Explanation:
By Gauss Law for electric field:

Where
is the charge density Q/A. Since we have 2 parallel plates with different charge, the electric field at point P in the gap would be the sum of 2 field



Answer:
The answer is "583.042533 MPa".
Explanation:
Solve the following for the real state strain 1:

Solve the following for the real stress and pressure for the stable.
![K=\frac{\sigma_{r1}}{[\In \frac{I_{il}}{I_{01}}]^n}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5Csigma_%7Br1%7D%7D%7B%5B%5CIn%20%5Cfrac%7BI_%7Bil%7D%7D%7BI_%7B01%7D%7D%5D%5En%7D)
Solve the following for the true state stress and stress2.

![=\frac{\sigma_{r1}}{[\In \frac{I_{il}}{I_{01}}]^n} \times [\In \frac{I_{i2}}{I_{02}}]^n\\\\=\frac{399 \ MPa}{[In \frac{54.4}{47.7}]^{0.2}} \times [In \frac{57.8}{47.7}]^{0.2}\\\\ =\frac{399 \ MPa}{[ In (1.14046122)]^{0.2}} \times [In (1.21174004)]^{0.2}\\\\ =\frac{399 \ MPa}{[ In (1.02663509)]} \times [In 1.03915873]\\\\=\frac{399 \ MPa}{0.0114161042} \times 0.0166818905\\\\= 399 \ MPa \times 1.46125948\\\\=583.042533\ \ MPa](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Csigma_%7Br1%7D%7D%7B%5B%5CIn%20%5Cfrac%7BI_%7Bil%7D%7D%7BI_%7B01%7D%7D%5D%5En%7D%20%5Ctimes%20%5B%5CIn%20%5Cfrac%7BI_%7Bi2%7D%7D%7BI_%7B02%7D%7D%5D%5En%5C%5C%5C%5C%3D%5Cfrac%7B399%20%5C%20MPa%7D%7B%5BIn%20%5Cfrac%7B54.4%7D%7B47.7%7D%5D%5E%7B0.2%7D%7D%20%5Ctimes%20%5BIn%20%5Cfrac%7B57.8%7D%7B47.7%7D%5D%5E%7B0.2%7D%5C%5C%5C%5C%20%3D%5Cfrac%7B399%20%5C%20MPa%7D%7B%5B%20In%20%281.14046122%29%5D%5E%7B0.2%7D%7D%20%5Ctimes%20%5BIn%20%281.21174004%29%5D%5E%7B0.2%7D%5C%5C%5C%5C%20%3D%5Cfrac%7B399%20%5C%20MPa%7D%7B%5B%20In%20%281.02663509%29%5D%7D%20%5Ctimes%20%5BIn%201.03915873%5D%5C%5C%5C%5C%3D%5Cfrac%7B399%20%5C%20MPa%7D%7B0.0114161042%7D%20%5Ctimes%200.0166818905%5C%5C%5C%5C%3D%20399%20%5C%20MPa%20%5Ctimes%201.46125948%5C%5C%5C%5C%3D583.042533%5C%20%5C%20MPa)
Answer:
Velocity of rock fall collision, v = 13.21 m/sec
Explanation:
Detailed explanation given in the attached document.
Answer:
A turbo blade has the best features from both other types of blade. The continuous, serrated edge makes for fast cutting while remaining smooth and clean. They are mostly used to cut a variety of materials, such as tile, stone, marble, granite, masonry, and many other building materials.
Explanation: