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Goryan [66]
4 years ago
13

Which pendulum will.mobe faster​

Engineering
1 answer:
Amiraneli [1.4K]4 years ago
5 0

Explanation:

The period T (i.e. time to make one complete swing)

of a pendulum of length L is

T = 2 pi sqrt(L/g)

where g=acceleration due to gravity.

Note that the period is independent (to first order) of mass.

This means that the shorter the string, the shorter is the time (i.e. faster) it takes to make a complete swring.

Since the 5 kg mass is attached to a shorter swing, it will "move" faster, or the period T is shorter.

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Answer:

Mogul executives takes samples of n=8 eagletrons at a time.

They found that the average is 3.25 mph.

For n = 8,

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The upper and lower control limits are found as

UCL =1.864 ×3.25= 6.058

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An object is supported by a crane through a steel cable of 0.02m diameter. If the natural swinging of the equivalent pendulum is
devlian [24]

Answer:

22.90 × 10⁸ kg

Explanation:

Given:

Diameter, d = 0.02 m

ωₙ = 0.95 rad/sec

Time period, T = 0.35 sec

Now, we know

T= 2\pi\sqrt{\frac{L}{g}}

where, L is the length of the steel cable

g is the acceleration due to gravity

0.35= 2\pi\sqrt{\frac{L}{9.81}}

or

L = 0.0304 m

Now,

The stiffness, K is given as:

K = \frac{\textup{AE}}{\textup{L}}

Where, A is the area

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or

K = \frac{\frac{\pi}{4}d^2\times2\times10^11}{0.0304}

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K = 20.66 × 10⁸ N

Also,

Natural frequency, ωₙ = \sqrt{\frac{K}{m}}

or

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or

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