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ss7ja [257]
4 years ago
12

The temperature controller for a clothes dryer consists of a bimetallic switch mounted on an electrical heater attached to a wal

l-mounted insulation pad. The switch is set to open at 70 °C, the maximum dryer air temperature. In order to operate the dryer at a lower air temperature, sufficient power is supplied to the heater such that the switch reaches 70 °C (Tset) when the air temperature T is less than Tset. If the convection heat transfer coefficient between the air and the exposed switch surface of 30 mm2 is 25 W/m2 ꞏ K.
Required:

How much heater power Pe is required when the desired dryer air temperature is T[infinity]=50°C?
Engineering
1 answer:
Naddika [18.5K]4 years ago
6 0

Answer:

0.015\ \text{W}

Explanation:

T_{set} = Set temperature = 70^{\circ}\text{C}

T_\infty = Air temperature = 50^{\circ}\text{C}

A = Surface area = 30\ \text{mm}^2=30\times 10^{-6}\ \text{m}^2

h = Convection heat transfer coefficient = 25\ \text{W/m}^2\text{K}

Heater power is given by

P_e=hA(T_{set}-T_\infty)\\\Rightarrow P_e=25\times 30\times 10^{-6}(70-50)\\\Rightarrow P_e=0.015\ \text{W}

The required heater power is 0.015\ \text{W}

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The heat transfer rate due to free convection from a vertical surface, 1 m high and 0.6 m wide, to quiescent air that is 20 K co
andreyandreev [35.5K]

Answer:

The ratio of heat transfer rate is 0.88

Explanation:

Given;

Case1 :

height of vertical surface, L = 1 m

width of vertical surface, w = 0.6 m

Case 2:

height of vertical surface, L = 0.6 m

width of vertical surface, w = 1 m

At an assumed film temperature of air = 300 K

then, read off from heat transfer table, temperature inverse β, surface area flow rate v, and Pr, to determine Rayleigh number for the two cases.

β = 1/300 = 0.00333 K⁻¹

v = 15.89 x 10⁻⁶ m²/s

Pr = 0.69

Case 1, L = 1 m

R_a = \frac{g\beta TL^3P_r}{v^2}

R_a = \frac{9.8*0.00333* 20*1^3*0.69}{(15.89x10^{-6})2} \\\\R_a = 1.784 *10^9

Case 2, L = 0.6 m

R_a = \frac{g\beta TL^3P_r}{v^2} \\\\R_a = \frac{9.8*0.00333* 20*0.6^3*0.69}{(15.89*10^{-6})^2}\\\\ R_a = 3.853 *10^8

From the values of Rayleigh numbers above, case 1 is Turbulent flow while case 2 is laminar flow

Thus: C₁ = 0.1, n₁ = ¹/₃

          C₂ = 0.59, n₂ = 1/4

Ratio of heat transfer rate is given as:

\frac{q_1}{q_2} = \frac{h_1 \delta T}{h_2 \delta T} \\\\\frac{q_1}{q_2} = \frac{h_1}{h_2} \\\\But, \frac{hL}{k} = CR_a^n L, \ \ h=\frac{k}{L}(CR_a^n L)\\\\\frac{q_1}{q_2} = \frac{C_1R_a_1^n L_2}{C_2R_a_2^n L_1} = \frac{0.1(1.784*10^9)^{\frac{1}{3}} *0.6}{0.59(3.853*10^8)^{\frac{1}{4}} *1} \\\\\frac{q_1}{q_2} = \frac{72.76}{82.66} = 0.88

Therefore, the ratio of heat transfer rate is 0.88

4 0
3 years ago
A 1.5-kg specimen of a 90 wt% Pb-10 wt% Sn alloy (Animated Figure 9.8) is heated to 250°C; at this temperature it is entirely an
Alex17521 [72]

Answer:

A. By hit and trial method 280 C

Explanation:

ion know B sorry

6 0
2 years ago
Which of the following is a safety device meant to protect an operator from the point of operation?
Art [367]

Answer:

machine guarding

Explanation:

Machine guarding protects an operator from the point of operation.

6 0
4 years ago
Acquisition of resources from an external source is called?
densk [106]

Answer:

subcontracting

Explanation:

I hope this is right

6 0
3 years ago
A closed tank contains ethyl alcohol to a depth of 66 ft. Air at a pressure of 23 psi fills the gap at the top of the tank. Dete
irina1246 [14]

Answer:

639.4psi

Explanation:

Pressure at the closed valve = Air pressure+ (density*gravity*height)

=23psi+(49.27lb/ft^3*32.17ft/s^2*56ft^3)

=23psi+88760.89psft

=23psi+(88760.89/144)psi

=23+616.4

=639.4psi

3 0
3 years ago
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