Answer:
specific volume = 1.025 m³/kg
Explanation:
given data
total mass m1 +m2 = 80 kg
specific volume = 0.8 m³/kg
occupies volume v1 = 40 m³
other gas specific volume = 1.4 m³
to find out
How much volume is occupied by the second gas and what is the specific volume of the mixture
solution
we know that density is reciprocal of specific volume and here gas is not interacting
so total specific volume is assume so ratio is total volume to total mass
and
specific volume = 
here ρ is density
so ρ1 = 
= 1.25 kg/m³
and ρ2 = 
= 0.714 kg/m³
and
so m1 = ρ1v1 = 1.25 × 40 = 50 kg
and m2 = 80 - 50 = 30 kg
so
v2 = 
v2 = 
= 42 m³
so volume occupied by second das = 42 m³
and
specific volume of mixture will be
specific volume of mixture = 
specific volume = 
specific volume = 1.025 m³/kg
Answer:
A retaining of a wall is a protective structure, first and foremost.
Explanation:
Its main aim is to provide functional support for keeping soil in place. It acts as a wall to keep the soil on one side and the rest of the landscape area on the other, providing a platform for a garden to be created.
Answer:
<u>Option 1</u>
Explanation:
As the team has already submitted the plans for the part drawing, the best way to proceed would be how it was given in the plans. Hence, the option to be selected :
- <u>Team member 1 suggests an orthographic top view because that is how the plans for the part were submitted.</u>
Answer: a 8143.71 kJ/kg
b 393.15 K
Explanation:
This system is an isobaric process in which there is no change in pressure a quasistatic process where a pressure distribution exists
a since no change in pressure =0 the system does work thus
FOR HELIUM properties in standard thermodynamic chart
cv = 3.1 kJ/kgK
M = Molar mass = 4 kg/kmol
R = Universal gas constant = 8.314 kJ/kg K
cp ≈ cv +R /M = 3.1 + 8.314 /4 = 5.1785 kJ/kgK
Cp = cp * M = 5.1785 kJ/kgK * 4 kg/kmol = 20.714 kJ/kgkmol
T = 120 °C to Kelvin = 120 + 273.15k = 393.15 K
W =n Cp ΔT = 1 kmol * 20.714 kJ/kg kmol* 393.15 K = 8143.71 kJ/kg
b convert T °C = T K thus 120 + 273.15 K = 393.15 K
P₁/T₁ = P₂/T₂
200 kPa/ 393.15 K = 200 kPa/T₂
T₂ = 200 kPa * 393.15 K/ 200 kPa = 393.15 K or 120 k
