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Yanka [14]
3 years ago
14

When a rocket is traveling toward a mountain at 100 m/s, the sound waves from this rocket's engine approach the mountain at spee

d V.
If the rocket doubles its speed to 200 m/s, the sound waves from the engine will now approach the mountain at speed

A. 2–√V
B. 2V
C. V
D. 4V
Physics
1 answer:
Charra [1.4K]3 years ago
3 0

Answer:

The correct option is C

Explanation:

From the question we are told that

  The initial speed of the rocket is  v_i = 100 m/s

    The speed of the rocket engine sound is V

    The final speed of the rocket is  v_f = 200 \ m/s

The speed of the sound at v_f would still remain V this because the speed of sound wave is constant and is not dependent on the speed of the observer(The mountain ) or the speed of the source (The rocket ).

  A clear example when  lightning strikes you will first see (that is because it travels at  the speed of light which is greater than the speed of sound) but it would take some time before you hear the sound of the   lightning

Here we see that the speed of the lightning(speed of sound) does not affect the speed of the sound it generates  

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A chain saw produces a spherical sound wave having a frequency of 214Hz in air at 358C (308.2K or 958F). At a distance of 600mm
Helen [10]

Given Information:

Frequency = 214 Hz

Temperature = 358° C = 308.2 K

Sound Pressure = p = 100 dB = 2 pascal

Distance = 600 mm = 0.60 m

Required Information:

(a) Acoustic Power Level = ?

(b) Acoustic Particle Velocity = ?

and Velocity level at a distance of 600 mm = ?

Answer:

Acoustic Power Level = Lw = 106.44 dB

Acoustic Particle Velocity = v = 0.0106 m/s

Velocity level = 60.25 dB

Explanation:

(a) Acoustic Power Level

Acoustic Power = W = 4πr² I

Acoustic Intensity = I =  p ²/Z₀

Where Z₀ is the characteristic impedance of air Z₀ = 409.8 rayl

I =  p ²/Z₀ = (2)²/409.8 = 0.00976 W/m²

W = 4πr² I = 4*π(0.60)²*0.00976 = 0.0441 W

Acoustic Power Level = Lw = 10log(W/Wref)

Where Wref is Reference Acoustic Power Wref = 1x10⁻¹² W

Lw = 10log(W/Wref) = 10log(0.0441/1x10⁻¹²) = 106.44 dB

Lw = 106.44 dB

(b) Acoustic Particle Velocity

Acoustic Particle velocity = v =  p ²/Zs

Where Zs is specific acoustic impedance

Zs =  Z₀kr/(1 + k²r²)⁰°⁵

Where k = 2πf/c and c = 346.1 m/s is the speed of sound in air

k = 2π*214/346.1 = 3.885 per m

Zs =  409.8*3.885*0.60/(1 + (3.885)²(0.60)²)⁰°⁵

Zs = 376.6 rayl

v =  p ²/Zs = 2²/376.6 = 0.0106 m/s

v = 0.0106 m/s

Velocity level = 10log(v/vref) where vref = 10x10⁻⁹ m/s

Velocity level = 10log(0.0106/10x10⁻⁹) = 60.25 dB

Velocity level = 60.25 dB

8 0
4 years ago
1 point
Tju [1.3M]

Answer:

Option A nuclear

Explanation:

The rate of electricity production in nuclear power plant is much higher as compared to the rate of electricity generation in gas, wind and solar power plants.

Thus, in case where large amount of electricity is to be produced in a short period then one must rely on nuclear power plants.

Therefore, option A is correct

7 0
3 years ago
What is the primary objective of the physical design phase of the secsdlc?
erastova [34]
To choose particular advancements to help the data security outline. A SecSDLC will display an extensive, repeatable, and predictable methodology for coordinating security into your application advancement process. It will include characterizing necessities, architecting the application, building and testing the application, conveying to creation, and keeping up the application underway.
6 0
4 years ago
Wall-E the robot is resting when he randomly explodes into two pieces that fly off in opposite directions. His head has a mass o
Brut [27]

Answer:

<em>The body flies off to the left at 9.1 m/s</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is  

P=mv.  

If we have a system of bodies, then the total momentum is the sum of the individual momentums:

P=m_1v_1+m_2v_2+...+m_nv_n

If a collision occurs and the velocities change to v', the final momentum is:

P'=m_1v'_1+m_2v'_2+...+m_nv'_n

Since the total momentum is conserved, then:

P = P'

In a system of two masses, the equation simplifies to:

m_1v_1+m_2v_2=m_1v'_1+m_2v'_2\qquad\qquad[1]

Wall-E robot is initially at rest, its two parts together. His head has a mass of m1=0.75 kg and his body has a mass of m2=6.2 kg. Both parts have initial speeds of zero v1=v2=0.

After the explosion, his head flies off to the right at v1'=75 m/s. We are required to find the speed of his body v2'. Solving [1] for v2':

\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}

Substituting values:

\displaystyle v'_2=\frac{0.75*0+6.2*0-0.75*75}{6.2}

\displaystyle v'_2=-9.1 \ m/s

The body flies off to the left at 9.1 m/s

3 0
3 years ago
if you transfer equal amounts of geat to 1kg of water and 1kg of cooper, which will change tempature more
Angelina_Jolie [31]

If you transfer equal amounts of geat to 1kg of water and 1kg of cooper, the temperature of the cooper will change more . . . it'll get more degrees warmer than the water will.

That's because the specific geat of water is greater than the specific geat of cooper.

(This just means it takes more geat to warm some mass of water by some amount than it takes to warm the same mass of cooper by the same amount.)  

4 0
3 years ago
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