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Yanka [14]
3 years ago
14

When a rocket is traveling toward a mountain at 100 m/s, the sound waves from this rocket's engine approach the mountain at spee

d V.
If the rocket doubles its speed to 200 m/s, the sound waves from the engine will now approach the mountain at speed

A. 2–√V
B. 2V
C. V
D. 4V
Physics
1 answer:
Charra [1.4K]3 years ago
3 0

Answer:

The correct option is C

Explanation:

From the question we are told that

  The initial speed of the rocket is  v_i = 100 m/s

    The speed of the rocket engine sound is V

    The final speed of the rocket is  v_f = 200 \ m/s

The speed of the sound at v_f would still remain V this because the speed of sound wave is constant and is not dependent on the speed of the observer(The mountain ) or the speed of the source (The rocket ).

  A clear example when  lightning strikes you will first see (that is because it travels at  the speed of light which is greater than the speed of sound) but it would take some time before you hear the sound of the   lightning

Here we see that the speed of the lightning(speed of sound) does not affect the speed of the sound it generates  

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Someone please help
saul85 [17]

Based on the attached image:

  • The name of the longitude line that passes through point A is the International Date Line
  • The longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.
  • The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° E
  • Longitude 120° is B
  • Solar time at Point B is 4 pm
  • The location will correspond to any point on the same latitude as A

<h3>What are lines of longitude?</h3>

Lines of longitude are imaginary lines which run along the earth from the North pole. to the South pole.

Longitude lines divide the earth into semi-circles.

Longitude lines are known as meridians and each meridian measures one arc degree of longitude.

Considering the attached image:

  • The name of the longitude line that passes through point A is the International Date Line
  • The longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.
  • The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° E
  • Longitude 120° is B
  • Solar time at Point B is 4 pm
  • the location will correspond to any point on the same latitude as A

In conclusion, longitude lines are imaginary lines and run from North to South on the earth.

Learn more about lines of longitude at: brainly.com/question/1939015

#SPJ1

8 0
2 years ago
Which of the following answers is NOT an example of repetition?
Step2247 [10]

Answer:

the first one.

Explanation: I don't exactly but, I know the other three sounds more like repetition! Hope this helps

5 0
3 years ago
Wo siblings are arguing over what way to pull a 10 kg wagon. Boris wants to pull it to the right. Boris puts 220 N of force on t
Mrrafil [7]

Answer:

a) Then net force acting on the wagon  30 [N] in a negative direction to the left

b)Acceleration of the wagon 3 m/s² in a negative direction to the left

Explanation:

The coordinates x and y show the positive direction in x-axis ( to the right) and negative direction to the left. In north-south direction positive y values are to the north and negative values to the south

The free-body diagram shows 4 forces acting

In y-axis:

The weight ( P = m*g =  10 [kg]*9,8 [m/s²] = 98 [N] negative

Normal reaction force  Fn = P = 98 [N]  positive ( surface is frictionless)

∑Fy = 0     P - Fn = 0     P = Fn  = 98 [N]

In x-axis:

Boris pulling force to the right (positive ) 220 [N]

Natasha pulling force to the left ( negative) 250 [N]

∑Fx = m*a

220 [N] - 250 [N]  = 10 Kg * a                      [N] = Kg * m /s²

-30 [kg*m/s²]  = 10 * Kg * a

-30/10  =  - 3  m/s²  = a

Sign (-) means the direction of acceleration vector is to the left (the same direction of the movement )

Then net force acting on the wagon  30 [N] in negative direction to the left

Acceleration of the wagon 3 m/s² in negative direction to the left

5 0
3 years ago
Identify characteristics of energy from the Sun. Check all that apply.
xxMikexx [17]

Answer:

First one, third one, and fourth one

6 0
3 years ago
Read 2 more answers
A delivery truck leaves a warehouse and travels 3.20 km east. The truck makes a right turn and travels 2.45 km south to arrive a
boyakko [2]

Explanation:

It is given that,

Displacement of the delivery truck, d_1=3.2\ km (due east)

Then the truck moves, d_2=2.45\ km (due south)

Let d is the magnitude of the truck’s displacement from the warehouse. The net displacement is given by :

d=\sqrt{d_1^2+d_2^2}

d=\sqrt{3.2^2+2.45^2}

d = 4.03 km

Let \theta is the direction of the truck’s displacement from the warehouse from south of east.

\theta=tan^{-1}(\dfrac{2.45}{3.2})

\theta=37.43^{\circ}

So, the magnitude and direction of the truck’s displacement from the warehouse is 4.03 km, 37.4° south of east.

8 0
3 years ago
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