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Yanka [14]
3 years ago
14

When a rocket is traveling toward a mountain at 100 m/s, the sound waves from this rocket's engine approach the mountain at spee

d V.
If the rocket doubles its speed to 200 m/s, the sound waves from the engine will now approach the mountain at speed

A. 2–√V
B. 2V
C. V
D. 4V
Physics
1 answer:
Charra [1.4K]3 years ago
3 0

Answer:

The correct option is C

Explanation:

From the question we are told that

  The initial speed of the rocket is  v_i = 100 m/s

    The speed of the rocket engine sound is V

    The final speed of the rocket is  v_f = 200 \ m/s

The speed of the sound at v_f would still remain V this because the speed of sound wave is constant and is not dependent on the speed of the observer(The mountain ) or the speed of the source (The rocket ).

  A clear example when  lightning strikes you will first see (that is because it travels at  the speed of light which is greater than the speed of sound) but it would take some time before you hear the sound of the   lightning

Here we see that the speed of the lightning(speed of sound) does not affect the speed of the sound it generates  

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assume the suns total energy output is 4.0 * 10^26 watts, and 1 watt is 1 joule/second. assume 4.3 * 10^-12 J is released from e
Dmitry [639]

Answer:

9.3\cdot 10^{37}

Explanation:

Power is defined as the energy produced (E) per unit of time (t):

P= \frac{E}{t}

This means that the energy produced in the Sun each second (1 s), given the power P=4.0\cdot 10^{26}W, is

E=Pt=(4.0\cdot 10^{26}W)(1s )=4.0\cdot 10^{26} J

Each p-p chain reaction produces an amount of energy of

E_1 = 4.3\cdot 10^{-12} J

in order to get the total number of p-p chain reactions per second, we need to divide the total energy produced per second by the energy produced by each reaction:

n=\frac{E}{E_1}=\frac{4.0\cdot 10^{26} J}{4.3\cdot 10^{-12} J}=9.3\cdot 10^{37}

3 0
3 years ago
Larger animals use proportionately less energy than smaller animals; that is, it takes less energy per kg to power an elephant t
marin [14]

Answer:

Part a)

Q = 952 cal/day

Part b)

P = 46 Watt

Part c)

\Delta P = 54 W

Explanation:

As we know that 5000 kg African elephant requires 70,000 Cal for basic needs per day

so we will have

m = 5000 kg

Q = 70,000 Cal

so we have energy required per kg

E = \frac{70,000}{5000}

E = 14 cal/kg

Part a)

now we know that per kg the energy required will be same

so we have mass of the human is 68 kg

so energy required per day is given as

Q = 68 \times 14

Q = 952 cal/day

Part b)

Resting power is the rate of energy in Joule required per sec

so it is given as

P = \frac{952 \times 4186}{24\times 3600}

P = 46 Watt

Part c)

resting power given in the book is

P' = 100 W

so this is less than the power given

\Delta P = 100 - 46

\Delta P = 54 W

6 0
3 years ago
The force that pulls falling objects toward Earth is called *
larisa [96]

Answer:

Gravity

Explanation:

That's easy because gravity is the only thing that can pull us down that hard at that fast without anything helping it.

5 0
3 years ago
Suppose you need your silicon circuit element to run continuously for 3 minutes before it shuts off long enough to cool back dow
Zigmanuir [339]

The maximum rate at which energy can be added to the circuit element mathematically given as

MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}

<h3>What is the maximum rate at which energy can be added to the circuit element?</h3>

Generally, the equation for P is  mathematically given as

P=\ln s \frac{\Delta T}{\Delta t}

Therefore

Rate\ of\ Change\ of\ Temp =\frac{p}{lnS}

\frac{p}{lnS}=\frac{7.4 \times 10^{-3}}{23 \times 10^{-6} \times 705}

\frac{p}{lnS}=0.456^{\circ \mathrm{c}} / \mathrm{sec}

Max temp Change

MaxT=5.6^{\circ} \mathrm{C}

\text { time }=3 \times 60

t=180s

In conclusion, Max Energy Rate

MER =23 \times 10^{-6} \times \frac{301 \times 5.6}{180}

MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}

Read more about  Energy

brainly.com/question/13439286

#SPJ1

3 0
2 years ago
A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axi
Hitman42 [59]

Answer:

the balls reached a height of 4.9985 m

Explanation:

Given the data in the question;

mass one m = 3.8 kg

mass two M = 2.1 kg

Initial velocities

u = 22 m/s

U = { moving downward} = 12 m/s

Now, using the law conservation of linear moment;

mu + MU = v( m + M )

we solve for "v" which is the velocity of the ball s after collision;

v = (mu + MU) / ( m + M )

so we substitute our given values into the equation

v = ( ( 3.8 × 22 ) + ( 2.1 × -12) ) / ( 3.8 + 2.1 )

v = ( 83.6 - 25.2 ) / 5.9

v = 58.4 / 5.9

v = 9.898 m/s

Now, we determine required height using the following relation;

v"² - v² = 2gh

where v" is the velocity at the top which is 0 m/s and g = -9.8 m/s²

0 - v² = 2gh

v² = -2gh

so we substitute

( 9.898 )² = -2 × -9.8  × h

97.97 = 19.6 × h

h = 97.97 / 19.6

h = 4.9985 m

Therefore, the balls reached a height of 4.9985 m

8 0
3 years ago
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