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klemol [59]
3 years ago
10

What is the common formula for work? Assume that W is the work, F is a constant force, 656-06-01-00-00_files/i0060000.jpgv is th

e change in velocity, and d is the displacement.
Physics
1 answer:
klio [65]3 years ago
6 0
The common formula for work is:
Work = force x displacement
W = F x d
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The answer is action potential 
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When hydrogen reacts with oxygen, hydrogen loses electrons. Which term
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Answer: Correct answer is A

Explanation: Ap3x appointment

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A torque of 36.5 N · m is applied to an initially motionless wheel which rotates around a fixed axis. This torque is the result
vivado [14]

Answer:

21.6\ \text{kg m}^2

3.672\ \text{Nm}

54.66\ \text{revolutions}

Explanation:

\tau = Torque = 36.5 Nm

\omega_i = Initial angular velocity = 0

\omega_f = Final angular velocity = 10.3 rad/s

t = Time = 6.1 s

I = Moment of inertia

From the kinematic equations of linear motion we have

\omega_f=\omega_i+\alpha_1 t\\\Rightarrow \alpha_1=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha_1=\dfrac{10.3-0}{6.1}\\\Rightarrow \alpha_1=1.69\ \text{rad/s}^2

Torque is given by

\tau=I\alpha_1\\\Rightarrow I=\dfrac{\tau}{\alpha_1}\\\Rightarrow I=\dfrac{36.5}{1.69}\\\Rightarrow I=21.6\ \text{kg m}^2

The wheel's moment of inertia is 21.6\ \text{kg m}^2

t = 60.6 s

\omega_i = 10.3 rad/s

\omega_f = 0

\alpha_2=\dfrac{0-10.3}{60.6}\\\Rightarrow \alpha_1=-0.17\ \text{rad/s}^2

Frictional torque is given by

\tau_f=I\alpha_2\\\Rightarrow \tau_f=21.6\times -0.17\\\Rightarrow \tau=-3.672\ \text{Nm}

The magnitude of the torque caused by friction is 3.672\ \text{Nm}

Speeding up

\theta_1=0\times t+\dfrac{1}{2}\times 1.69\times 6.1^2\\\Rightarrow \theta_1=31.44\ \text{rad}

Slowing down

\theta_2=10.3\times 60.6+\dfrac{1}{2}\times (-0.17)\times 60.6^2\\\Rightarrow \theta_2=312.03\ \text{rad}

Total number of revolutions

\theta=\theta_1+\theta_2\\\Rightarrow \theta=31.44+312.03=343.47\ \text{rad}

\dfrac{343.47}{2\pi}=54.66\ \text{revolutions}

The total number of revolutions the wheel goes through is 54.66\ \text{revolutions}.

3 0
2 years ago
A technician attaches one lead of a digital voltmeter to the ground terminal of the TP sensor and the other meter lead to the ne
wariber [46]

Answer:

Neither A or B

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sensor ground circuit does not has excessive resistance.

5 0
3 years ago
10. Hamilton How long does it take Lewis travelling at 156 m.p.h to cover 16 miles?
Anvisha [2.4K]

Answer: Hello!

Lewis is travelling at 165 mph, which means miles per hour, this says that he does 165 miles in one hour.

We want to know how much time takes to cover 16 miles.

this can be calculated as the quotient of the distance and the velocity; this is:

t = \frac{16 mi}{165 mi/h} = 0.096 h

if we want to write this in minutes, then:

we know that one hour has 60 minutes, then 0.096 hours has:

0.096h*60mins/1h = 5.8 minutes.

then Lewis needs 5.8 minutes in order to cover 16 miles if his speed is 156 miles per hour.

6 0
3 years ago
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