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VashaNatasha [74]
3 years ago
13

1) Two cars both moving at 27m/s (60mile/hr) pass each other on a road, one moving east the othe other west. 1a) both cars have

the same speed (T, F)
1b) both cars have the same velocity (T, F)
Physics
1 answer:
Igoryamba3 years ago
5 0

Answer:

1a) True  1b) False

Explanation:

The definition of a car's velocity is the change of displacement between time, from here we can see that this is a vector, this means that it has magnitude and direction.

The definition of speed is the change of distance between the unit of time, as we see this magnitude is a scalar since distance is a scalar.

1 a) the car has the same speed, True since the magnitude is a scalar

1 b) the cars have the same speed. False since the magnitude is a vector, even if it has the same module it has different direction

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A proton and an electron traveling with the same velocity enter a uniform electric field. compared to the acceleration of the pr
kenny6666 [7]
The acceleration of the electron is larger than the acceleration of the proton.

The reason for this is that the mass of the electron is smaller (about 1000 times smaller) than the mass of the proton. The two particles have same charge (e), so they experience the same force under the same electric field E:
F=eE 
However, according to Newton's second law, the force is the product between the mass particle, m, and its acceleration, a:
F=ma 
which can be rewritten as
a= \frac{F}{m}
we said that the force exerted on the two particles, F, is the same, while the mass of the electron is smaller: therefore, from the last formula we see that the acceleration of the electron will be larger than that of the proton.

6 0
3 years ago
Before colliding, the momentum of block A is -100 kg*m/, and block B is -150 kg*m/s. After, block A has a momentum -200 kg*m/s.
rjkz [21]

Answer:

Momentum of block B after collision =-50\ kg\ ms^{-1}

Explanation:

Given

Before collision:

Momentum of block A = p_{A1}= -100\ kg\ ms^{-1}

Momentum of block B = p_{B1}= -150\ kg\ ms^{-1}

After collision:

Momentum of block A = p_{A2}= -200\ kg\ ms^{-1}

Applying law of conservation of momentum to find momentum of block B after collision p_{B2}.

p_{A1}+p_{B1}=p_{A2}+p_{B2}

Plugging in the given values and simplifying.

-100-150=-200+p_{B2}

-250=-200+p_{B2}

Adding 200 to both sides.

200-250=-200+p_{B2}+200

-50=p_{B2}

∴ p_{B2}=-50\ kg\ ms^{-1}

Momentum of block B after collision =-50\ kg\ ms^{-1}

6 0
3 years ago
a moving ball rolls into a stationary ball. the total momentum of both balls after the collision will be
rosijanka [135]
The momentum of the rolling ball will have less momentum than before the collision and the stationary ball will have more momentum after the collusion.
5 0
3 years ago
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The weight of a box is 1200 Newton if it exerts a pressure of 800 Pascal calculate the area​
fomenos

Answer:

  1. 1.5m2

Explanation:

P=F/A. So here the force is given and the pressure is also given so you make the area the subject since that is what u are looking for

5 0
3 years ago
Radiation in the ultraviolet region of the electromagnetic spectrum is quite energetic. It is this radiation that causes dyes to
N76 [4]

The  energy of photon in kJ/mol is 329kJ/mol.

Wavelength of radiation is 370nm. The frequency of given wavelength is

            ν = c / λ

            ν = 3×10^8 / 370×10^-9

            ν = 8.11 × 10^14 s^-1

      Now the energy of photon is:

             E = hν

             E = 6.63×10^-34  J.s/photon × 8.11×10^14s^-1

             E = 5.41× 10^-19  J/photon

         To find in mole

              E = 5.41× 10^-19 × 6.022×10^23

               E = 3.29 ×10^ 5 J/mol

   So, the energy of mole of photon is equal to 329 kJ/mol.

        Learn more about radiation here:

                brainly.com/question/18650102

                     #SPJ4  

5 0
2 years ago
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