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Ivenika [448]
3 years ago
12

What what is the change in internal energy if 500 joule of heat is added to a system and 125 joule of work are done on a system

Physics
1 answer:
eduard3 years ago
8 0

Answer:

DU = 375 Joules

Explanation:

Given the following data;

Quantity of heat = 500 Joules

Work done = 125 Joules

To find the change in internal energy;

Mathematically, the change in internal energy of a system is given by the formula;

DU = Q - W

Where;

  • DU is the change in internal energy.
  • Q is the quantity of energy.
  • W is the work done.

Substituting into the formula, we have;

DU = 500 - 125

<em>DU = 375 Joules</em>

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Hope this helps:)

3 0
3 years ago
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if the Horse and Rider have a combined mass of 572 kg what force would be required to accelerate them 5 kph per second
Vlad [161]

Answer:

   Force required to accelerate = 794.44 N

Explanation:

 Force required = Mass of horse x Acceleration of horse

 Mass of horse and rider, m=   572 kg

 Acceleration of horse and rider, a = 5 kph per second

                                      =\frac{5*1000}{60*60} =1.39 m/s^2

  Force required = ma

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8 0
3 years ago
Consider a steel guitar string of initial length L=1.00 meter and cross-sectional area A=0.500 square millimeters. The Young's m
Reil [10]

Answer:

\Delta l=0.015m

Explanation:

We have given initial length of the steel guitar l = 1 m

Cross sectional area A=0.5mm^2=0.5\times 10^{-6}m^2

Young's modulus \gamma=2\times 10^{11}Pa

Force F = 1500 N

So stress =\frac{force}{area}=\frac{1500}{0.5\times 10^{-6}}=3000\times 10^{-6}=3\times 10^{9}Pa

We know that young's modulus =\frac{stress}{strain}

So 2\times 10^{11}=\frac{3\times 10^{9}}{strain}

strain=1.5\times 10^{-2}=0.015m

Now strain =\frac{\Delta l}{l}

0.015=\frac{\Delta l}{1}

\Delta l=0.015m

6 0
3 years ago
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The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given b
Mnenie [13.5K]

Explanation:

The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given by :

Q=t^3-2t^2+4t+4

We need to find the current flowing. We know that the rate of change of electric charge is called electric current. It is given by :

I=\dfrac{dQ}{dt}\\\\I=\dfrac{d(t^3-2t^2+4t+4)}{dt}\\\\I=3t^2-4t+4

At t = 1 s,

Current,

I=3(1)^2-4(1)+4\\\\I=3\ A

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For lowest current,

\dfrac{dI}{dt}=0\\\\\dfrac{d(3t^2-4t+4)}{dt}=0\\\\6t-4=0\\\\t=0.67\ s

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7 0
3 years ago
True or false Scientific endeavor is driven by both simple curiosity as well as societal demands
ICE Princess25 [194]

Answer:

its true that Scientific endeavor is driven by both simple curiosity as well as societal demands.

Explanation:

When a scientist has a curiosity about something he carried out a research. and when their is a demand of something in society that time scientific research is carried out. Therefore its true that a scientific endeavor is driven by  simple curiosity or societal demand.

For example

in society, there is demand of a medicine which can completely kill the cancer  and a scientist has curiosity to know how to kill cancer cell. In this way a scientific endeavor for cancer medicine can be carried out by both simple curiosity as well as societal demands.

6 0
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