Explanation:
Given that,
The initial velocity of an arrow is 23.4 m/s
We need to find the time taken by it to reach its maximum height. Let the maximum height is h.
Using third equation of motion to find height first.
At maximum height, v = 0
a = -g
Let t is the time to reach its maximum height. So, it can be calculated using second equation motion as follows :
Hence, it will take 2.35 seconds to reach its maximum height.
Answer:
50
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98 m √
How about s = Vo * t + ½at² ?
s = h = Vo * 2s - 4.9m/s² * (2s)² = 2Vo - 19.6
and
h = Vo * 10s - 4.9m/s² * (10s)² = 10Vo - 490
Subtract 2nd from first:
0 = -8Vo + 470.4
Vo = 58.8 m/s
h = 58.8m/s * 2s - 4.9m/s² * (2s)² = 98 m