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aniked [119]
3 years ago
13

Which of the following two combinations of reactants is more appropriate for the preparation of p-nitrophenyl phenyl ether? Fluo

robenzene and sodium p-nitrophenoxide, or p-fluoronitrobenzene and sodium phenoxide.

Chemistry
1 answer:
VladimirAG [237]3 years ago
5 0

Answer:

p-fluoronitrobenzene and sodium phenoxide is more appropriate

Explanation:

An ipso substitution is required to form p-nitrophenyl phenyl ether.

For this ipso substitution, an alkoxide anion needs to attack as a nucleophile at the carbon atom attached to fluorine atom and thereby substitute that F atom.

p-nitrophenoxide is an weak nucleophile as compared to phenoxide due to presence of electron withdrawing resonating effect of nitro group at para position.

p-fluoronitrobenzene is a good choice for nucleophilic attack by alkoxide anion as compared to fluorobenzene due to higher positive charge density at carbon atom directly attached to F atom. Higher positive charge density arises due to presence of electron withdrawing resonating effect og nitro group at para position.

So, p-fluoronitrobenzene and sodium phenoxide is more appropriate

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describe how astronomers are able to use the light from a distant star to determine what elements make up the stars.
dlinn [17]

Answer:

The spectra of the Sun and stars exhibited bright and dark lines called Fraunhofer lines. These were shown to be caused by elements emitting or absorbing light at specific wavelengths. Because each element emits or absorbs light only at specific wavelengths, the chemical composition of stars can be determined.

7 0
3 years ago
2.5 gm of a sample of Nahco3 when strongly.
mr_godi [17]

Answer:

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Explanation:

3 0
3 years ago
4. The reaction of silver nitrate and potassium bromide yields silver bromide and potassium nitrate. If
Hatshy [7]

Answer:

1.) AgNO₃

2.) 0.563 moles AgBr

Explanation:

The limiting reagent is the reagent that is used up completely during a reaction. It can be identified by calculating which reactant produces the smallest amount of product. This can be done by determining the number of moles of each reagent (via molarity conversion). and then converting it to moles of the product (via mole-to-mole ratio).

AgNO₃ (aq) + KBr (aq) ---> AgBr (s) + KNO₃ (aq)

Molarity (M) = moles / liters

100 mL = 1 L

AgNO₃

45.0 mL / 100 = 45.0 L

1.25 M = ? moles / 0.450 L

? moles = 0.563 moles

KBr

75.0 mL / 100 = 0.750 L

0.800 M = ? moles / 0.750 L

? moles = 0.600 moles

In this case, there is no need to use the mole-to-mole ratio because all of the coefficients are one in the reaction (the amount of the limiting reagent used is the same amount of product produced). Since AgNO₃ produces the smaller amount of product, it is the limiting reagent.

4 0
2 years ago
A different mass of sodium hydroxide was used to make another 25.0 cm' solution.
Dmitriy789 [7]

0.003 moles of NaOH was used in the titration.

<h3>What is titration?</h3>

The concentration of an identified analyte can be found using a simple laboratory technique called titration. As a standard solution with a given concentration and volume, a reagent known as the titrant or titrator is created.

By using a solution with a known concentration to measure the concentration of an unknown solution, this process is known as titration. To a known volume of the analyte (the unknown solution), the titrant (the known solution) is typically added from a buret until the reaction is finished. To ascertain the unknown concentration of an identifiable analyte, titration, commonly referred to as titrimetry, is a widely used quantitative laboratory analytical technique (Medwick and Kirschner, 2010). Volume measurements are a crucial component of titration

Concentration in mol/dm3 =

Amount of solution mol

= concentration in mol/dm3 × volume in dm3

Amount of sodium hydroxide

= 0.100 × 0.0250

= 0.00250 mol

To know more about titration, visit:

brainly.com/question/27394328

#SPJ9

6 0
1 year ago
PLEASE HELP MEEEEEEEEEEEEEEEEE
RSB [31]
The answer is the second choice.
5 0
3 years ago
Read 2 more answers
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