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Natalija [7]
3 years ago
5

Since water can be prepared in the laboratory

Chemistry
1 answer:
Arturiano [62]3 years ago
7 0

Answer:

# In a familiar high-school chemistry demonstration, an instructor first uses electricity to split water into its constituent gases, Hydrogen and Oxygen. Then, by combining the two gases and igniting them with a spark, the instructor changes the gases back into water with a loud pop (That means the energy is released in the process).

# There are new other ways to produce water in laboratory, however, the scientists can not produce water in large quantity for the masses, because of some reasons.

1- Theoretically, this is possible, but it would be an extremely dangerous process. Since Hydrogen is extremely flammable and Oxygen supports combustion, it wouldn’t take much to create this force, but we also have an explosion. That’s why this process can be a deadly one if our experiment is big enough.

2- Personally, I think that it makes no sense to produce water in a laboratory ( or in a large plant) for people to use as daily water. The much more important thing we need to do is to save our environment, our planet Earth. Because the daily water people drink contains not just water molecules but other minerals, the marine life is depend not just in water molecules but diferent factors, etc.

Explanation:

This is just my personal opinion. Hope that can help you a little. Have a nice day

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The density of water is 1 gm/ml. An object has a mass of 58 grams. What volume must it have in order to float in water?
Keith_Richards [23]

Answer:

58mL

Explanation:

Given parameters:

Density of water  = 1g/mL

Mass of object  = 58g

Unknown:

The volume the object must have to be able to float in water = ?

Solution:

To solve this problem, we know that the object must have density value equal to that of water or less than that of water to be able to float.

We then set its density to that of water;  

   Density  = \frac{mass}{volume}  

      Volume  = \frac{mass}{density}  

So;

      Volume  = \frac{58}{1}   = 58mL

7 0
3 years ago
What is 1/4 cup of magnesium converted to grams
ahrayia [7]

Answer: 32 grams

Explanation:

8 0
3 years ago
How do you determine the correct subscripts in a chemical formula
VMariaS [17]

BY CHECKING THE REACTIVITY OF AN ELEMENT WHICH IS MOST REACTIVE OR NOT AND YOU STUDY TYPE OF CHEMICAL REACTION IN 1 CH AND YOU CHECK THE REACTIVITY OF ELEMENTS IN 3 CH METALS AND NON METALS PAGE NO 45 IN NCERT BOOK

4 0
3 years ago
To whoever helps me thank you so much have a wonderful day!
Schach [20]

Answer:

N and P

Explanation:

Anion:

When an atom gain the electrons anion is formed. The negative sign shows that atom gain electron because number of electron are greater than protons or we can say that negative charge becomes greater than positive charge.

Cation:

When atom lose electron cation is formed. The atom thus have positive charge because number of positive charge i.e protons are increased are greater than negative charge or electron.

In given problem N and phosphorus both can gain three electrons which means negative charge becomes greater that's why the extra electron gained by atoms are written as -3 and both form anion with charge -3.

while Al form cation with charge +3 Mg form cation with charge +2 and iodine and bromine both form anion with charge of -1.

8 0
3 years ago
Two hydrogen atoms collide in a head on collision and end up with zero kinetic energy. Each then emits a photon of 121.6 nm (n=2
Zinaida [17]

Explanation:

Expression for the kinetic energy is as follows.

         K.E = \frac{1}{2}mv^{2}

Now, total kinetic energy will be as follows.

    K.E = 2 \times \frac{1}{2}mv^{2} = m \times v^{2}

Since, this energy converts into electromagnetic radiation of wavelength 121.6 nm.

Relation between energy and photon is as follows.

   Energy of photon = \frac{hc}{\lambda}

                                = \frac{6.626 \times 10^{-34} \times 3 \times 10^{8}}{121.6 \times 10^{-9}}

                                 = 1.63 \times 10^{-18} J

    m \times v^{2} = 1.63 \times 10^{-18}

          v = \sqrt{\frac{1.63 \times 10^{-18}}{1.67 \times 10^{-27}}

             = 3.12 \times 10^{4} m/s

Thus, we can conclude that atoms were moving at a speed of 3.12 \times 10^{4} m/s before the collision.

8 0
4 years ago
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