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vredina [299]
3 years ago
9

An injured monkey sits perched on a tree branch 4.5 m above the ground, while a wildlife veterinarian is kneeling down in the bu

shes 85.5 m away attempting to subdue the monkey with a tranquilizer gun. The vet knows that the moment the gun fires, the monkey will be frightened and fall down from the branch. At what angle up from the ground must the veterinarian aim the gun so that the tranquilizer dart will hit the falling monkey
Physics
1 answer:
garri49 [273]3 years ago
6 0

Answer:

3.03°

Explanation:

Given that

Height of the tree branch, h = 4.5 m

Distance of the veterinarian away, d = 85.5 m

The vet is to aim at the monkey at a particular angle. If we consider the force of gravity that will be acting on the dart. Then the angle that will be needed will be calculated as this.

So the angle is

Tan θ = opposite / adjacent

Tan θ = 4.5 m/ 85.5 m

Tan θ = 0.053, then

θ = Tan^-1 (0.053)

θ = 3.03°

Therefore, the angle needed is 3.03°

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The total momentum of two marbles before a collision is 0.06 kg-m / s. no outside forces act on the marbles. what is the total m
SpyIntel [72]
Hi my friend, since momentum is always conserved without external forces, the momentum after the collosion will still be 0.06 kg*m/s. Hope it helps☺
4 0
3 years ago
A uniform thin rod of length 0.11 m and mass 4.6 kg can rotate in a horizontal plane about a vertical axis through its center. T
ale4655 [162]

Answer:

Explanation:

This problem is based on conservation of rotational momentum.

Moment of inertia of rod about its center

= 1/12 m l² , m is mass of the rod and l is its length .

= 1 / 12 x 4.6 x .11²

I = .004638 kg m²

The angular momentum of the bullet about the center of rod = mvr

where m is mass , v is perpendicular component of velocity of bullet and r is distance of point of impact of bullet fro center .

5 x 10⁻³ x v sin60 x .11 x .5  where v is velocity of bullet

According to law of conservation of angular momentum

5 x 10⁻³ x v sin60 x .11 x .5 = ( I + mr²)ω , where ω is angular velocity of bullet rod system and  ( I + mr²) is moment of inertia of bullet rod system .

.238 x 10⁻³ v = ( .004638 + 5 x 10⁻³ x .11² x .5² ) x 12

.238 x 10⁻³ v = ( .004638 + .000015125 ) x 12

.238 x 10⁻³ v = 55.8375 x 10⁻³

.238 v = 55.8375

v = 234.6 m /s

4 0
3 years ago
Gracie chases the Frisbee for a displacement of 4.35 m while traveling 6.35 m/s. For how much time was Gracie running?
Tanya [424]

Answer:

2.34

Explanation:

5 0
3 years ago
Read 2 more answers
1 Peliminary Questions:
Scilla [17]

The time of flight depends only on the initial velocity and the initial height

Explanation:

An object is said to be in free fall if the only force acting on it is the force of gravity. If this is the case, then the motion of the object in free fall is a uniformly accelerated object, with constant acceleration g=9.8 m/s^2 towards the ground. The time of flight can be found by using the suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the displacement (which corresponds to the initial height of the object)

u is the initial vertical velocity

a=g is the acceleration

t is the time of flight

Therefore, from the equation, we see that the time of flight depends only on two factors:

  • s, the initial height of the object
  • u, its initial velocity

In case the air resistance is not negligible, then the acceleration is no longer constant, and the time of the fall also depends on other factors such as the mass of the object and its shape, which affects the magnitude of the air resistance acting on the body.

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

7 0
3 years ago
A car of mass 1270 kg makes a 15.0 m radius turn at 11.8 m/s on flat ground. How much centripetal force acts on it?
svp [43]

Answer:

Centripetal force = 11789 N

Explanation:

Recall that the centripetal acceleration is defined as the square of the tangential velocity divided by the radius of the circular rotation. Then for our case, the centripetal acceleration is:

ac = (11.8 m/s)^2 / 15 m = 9.28266 m/s^2

then, such acceleration on a mass of 1270 kg will render a centripetal force of:

Fc = m * ac = 1270 * 9.28266 N = 11789 N

3 0
3 years ago
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