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Gelneren [198K]
3 years ago
5

A segull flying horizontally at 15m/s drops a clam. The clam takes 3.0sec to hit the ground. How high was the seagull when the c

lam was dropped ?
Need formula and answer
Physics
1 answer:
lora16 [44]3 years ago
7 0

The distance a dropped object falls, with gravity and no air resistance:

Distance = (1/2) (acceleration) (falling time)²

Without air resistance, the horizontal motion has no effect on the fall.

Acceleration of Earth gravity = 9.8 m/s²

Distance = (1/2) (acceleration) (falling time)²

Distance = (1/2) (9.81 m/s²) (3.0 s)²

Distance = (0.5) x (9.81 m/s²) x (9.0 s²)

Distance = (0.5 x 9.81 x 9.0) (m-s² / s²)

Distance = 44.15 meters

We don't care how fast the bird was flying horizontally.  It doesn't change anything.  (It DOES determine how far ahead of the drop point the clam hits the ground.  Most problems like this ask for that distance.  This one didn't.)

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A uniform plank of mass 10kg and length 10m rests on two supports, A and B as shown. A boy of weight 500N stands at a distance o
kifflom [539]

Answer:

U² = 142.86 N

U¹ = 357.14 N

Explanation:

Taking summation of the moment about point A, we get the following equilibrium equation: (taking clockwise direction as positive)

W(2\ m) - U^2(7\ m) = 0

where,

W = weight of boy = 500 N

U² = reaction ay B = ?

Therefore,

(500\ N)(2\ m)-(U^2)(7\ m)=0\\U^2=\frac{1000\ Nm}{7\ m}\\

<u>U² = 142.86 N</u>

Now, taking summation of forces on the plank. Taking upward direction as positive, for equilibrium position:

W-U^1-U^2=0\\500\ N - 142.86\ N = U^1\\

<u>U¹ = 357.14 N</u>

3 0
3 years ago
A nitrogen isotope has an atomic number of 7 and an atomic mass of 15. the respective numbers of neutrons, protons, and electron
anygoal [31]
Atomic Number = amount of protons. Atomic mass = protons (7) and neutrons (8)


Electrons will be the protons - any charge the isotope has. For example, a +2 charge would make the electrons 7- (+2) = 5. A -2 charge would be electrons 7 - (-2) = 9
6 0
3 years ago
Part Two: Criteria, Constraints, and Prioritizations
AlexFokin [52]

Answer:

Usually, a solution can have several criteria and constraints. Even though all are important, some criteria are more important than others. The same holds true for constraints. But what do you do if it's impossible for a solution to cover every criterion while avoiding every constraint? In cases like this, you can use prioritization. Listing criteria and constraints based on priority shows the relative importance of each. You will need to prioritize the criteria and constraints for each sub-problem so that you can design a solution for each one individually. Prioritization can help you compare two different possible solutions. For example, the criterion that cars travel at 15 mph through the neighborhood might be a higher priority than the constraint that homeowners are only willing to spend $10,000 on this issue. If this is the case, you would want to generate solutions that also follow the priority in mind. All criteria are important, but engineers must sometimes make a trade-off, which is a compromise or change in one or more criteria or constraints so that they can be met at the same time. This is where prioritization comes in handy as it helps determine the trade-offs. A solution that is doing a better job of meeting one criterion may result in not completely meeting another criterion. Prioritization will help you choose which solution to go with.

Explanation:

I got this from quizlet :)

7 0
2 years ago
Two steel guitar strings have the same length. String A has a diameter of 0.513 mm and is under 403 N of tension. String B has a
Mnenie [13.5K]

Answer:

\frac{v_{A}}{v_{B}} = 1.785

Explanation:

T_{A} = Tension force in string A = 403 N

T_{B} = Tension force in string B = 800 N

d_{A} = diameter of string A = 0.513 mm

d_{B} = diameter of string B = 1.29 mm

v_{A} = wave speed of string A

v_{B} = wave speed of string B

Ratio of the wave speeds is given as

\frac{v_{A}}{v_{B}} = \sqrt{\frac{T_{A}}{T_{B}}} \left ( \frac{d_{B}}{d_{A}} \right )

\frac{v_{A}}{v_{B}} = \sqrt{\frac{403}{800}} \left ( \frac{1.29}{0.513} \right )

\frac{v_{A}}{v_{B}} = 1.785

5 0
3 years ago
This refers to the bending of a wave as it crosses a boundary between two media at an angle
Evgesh-ka [11]
The bending of a wave as it crosses a boundary between 2 mediums at an angle is called refraction.
3 0
3 years ago
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