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Gelneren [198K]
3 years ago
5

A segull flying horizontally at 15m/s drops a clam. The clam takes 3.0sec to hit the ground. How high was the seagull when the c

lam was dropped ?
Need formula and answer
Physics
1 answer:
lora16 [44]3 years ago
7 0

The distance a dropped object falls, with gravity and no air resistance:

Distance = (1/2) (acceleration) (falling time)²

Without air resistance, the horizontal motion has no effect on the fall.

Acceleration of Earth gravity = 9.8 m/s²

Distance = (1/2) (acceleration) (falling time)²

Distance = (1/2) (9.81 m/s²) (3.0 s)²

Distance = (0.5) x (9.81 m/s²) x (9.0 s²)

Distance = (0.5 x 9.81 x 9.0) (m-s² / s²)

Distance = 44.15 meters

We don't care how fast the bird was flying horizontally.  It doesn't change anything.  (It DOES determine how far ahead of the drop point the clam hits the ground.  Most problems like this ask for that distance.  This one didn't.)

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Cart a having a mass of 150 kg initially moving to the right at a speed of 8 m/s collides with cart b with a mass of 150 kg, ini
kakasveta [241]

The speed of cart b is 6m/s while the total momentum of the systmen is 4200 kg m/s

<h3>Conservation of Linear Momentum</h3>

Given Data

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  • Final VelocityV1 = 5 m/s

Mass of cart two M2  = 150kg

Velocity U2 = 6m/s

Applying the principle of conservation of linear momentum we have

M1U1+M2U2 = M1V1+ M2V2

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substituting our given data we have

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b. what is the total momentum of the system before and after collision

Total Momentum in the system is

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Total momentum = 1200 + 900 + 1200+ 900

Total momentum = 4200 kg m/s

Learn more about Conservation of Linear Momentum here:

brainly.com/question/7538238

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there are some important considerations in optical fiber communications these are.

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