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3 years ago

If you weigh 499N on earth how much do you weigh on the moon?

Physics

2 answers:

ANEK [815]3 years ago

7 0

Well, if you were on the moon, you'd lose 6 times has much physical weight than you did on earth! So (AROUND) 90N!

vivado [14]3 years ago

4 0

The Moon's gravity (on the surface) is roughly
1/6 of the Earth's gravity (on the surface).

So, on the Moon, you would weigh about

(1/6) x (499 N) = about 83 N .

( more-accurate number: 82.56 N )

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Jared is reading an article about the heavy rains that have fallen recently in his town. But he can’t separate the facts from th

Crank

<span>FACTS:
|
|
It’s that time of year again when the days are wet and cool.
   The rainy season is the best season.
Rain makes up part of Earth’s water cycle.
Water evaporates from streams, lakes, and oceans, then condensation
   and precipitation occur in the form of rain.
   Precipitation in the form of rain is better than snow.
   Snow this time of year makes people gloomy.
Rain is a great boon to local farmers.
It helps their crops grow.

</span>OPINIONS:
|
<span>|   It’s that time of year again when the days are wet and cool.
The rainy season is the best season.
   Rain makes up part of Earth’s water cycle.
   Water evaporates from streams, lakes, and oceans, then condensation
and precipitation occur in the form of rain.
Precipitation in the form of rain is better than snow.
Snow this time of year makes people gloomy.
   Rain is a great boon to local farmers.
   It helps their crops grow.</span>

6 0

3 years ago

Read 2 more answers

The lawn sprinkler consists of four arms that rotate in the horizontal plane. The diameter of each nozzle is 8 mm, and the water

sashaice [31]

Answer: the constant angular velocity of the arms is 86.1883 rad/sec

Explanation:

First we calculate the linear velocity of the single sprinkler;

Area of the nozzle = π/4 × d²

given that d = 8mm = 8 × 10⁻³

Area of the nozzle = π/4 × (8 × 10⁻³)²

A = 5.024 × 10⁻⁵ m²

Now total discharge is dived into 4 jets so discharge for single jet will be;

Q_single = Q / n = 0.006 / 4 = 1.5 × 10⁻³ m³/sec

So using continuity equation ;

Q_single = A × V_single

V_single = Q_single/A

we substitute

V_single = (1.5 × 10⁻³) / (5.024 × 10⁻⁵)

V_single = 29.8566 m/s

Now resolving the forces as shown in the second image,

Vt = Vcos30°

Vt = 29.8566 × cos30°

Vt = 25.8565 m/s

Finally we calculate the angular velocity;

Vt = rω

ω_single = Vt / r

from the given diagram, radius is 300mm = 0.3m

so we substitute

ω_single = 25.8565 / 0.3

ω_single = 86.1883 rad/sec

Therefore the constant angular velocity of the arms is 86.1883 rad/sec

7 0

3 years ago

For an isolated system, the sum of the kinetic and potential energies

Elenna [48]

I am pretty sure the answer to your question is B

4 0

2 years ago

Read 2 more answers

The current through a 10-ohm resistor connected to a 120-V power supply is The current through a 10-ohm resistor connected to a

Mazyrski [523]

Answer:

12 A

Explanation:

V= I * R

V/R = I

120 V /10 Ω = 12 AMPS

7 0

1 year ago

Power is the rate at which energy is transformed. A person is limited in the total work he or she can do only by the total energ

Sergio039 [100]

Answer:

Power is the rate at which energy is transformed.

The SI unit of power is the watt.

Power is the rate at which work is done.

Explanation:

In this question we have to choose the statements related to Power that are True.

In this sense, Power $P$ is the speed with which work $W$ is done. Its unit is Watts ( $W$ ), being $1 W=\frac{1 Joule}{1 s}$ .

Power is mathematically expressed as:

$P=\frac{W}{t}$

Where $t$ is the time during which work $W$ is performed.

On the other hand, the Work $W$ done by a Force $F$ refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path. It is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter ( $1J=(1N)(1m)=Nm$ ).

So, according to this explanation, the true statements are:

Power is the rate at which energy is transformed.

The SI unit of power is the watt.

Power is the rate at which work is done.

4 0

3 years ago