Two rods, one made of brass and the other made of copper, are joined end to end. The length of the brass section is 0.400 m and
1 answer:
You might be interested in
Answer:
Coil 2 have 235 loops
Explanation:
Given
The number of loops in coil 1 is n ₁= 159
The emf induced in coil 1 is ε ₁ = 2.78 V
The emf induced in coil 2 is ε ₂ = 4.11 V
Let
n ₂ is the number of loops in coil 2.
Given, the emf in a single loop in two coils are same. That is,
ϕ ₁/n ₁= ϕ ₂ n ₂⟹ 2.78/159 = 4.11/ n ₂
n₂=
n₂=235
Therefore, the coil 2 has n ₂= 235 loops.
Answer:
The resistance is 0.124 ohm.
Explanation:
It is common for domestic electrical installations to use copper wire with a diameter of 2.05 mm. Determine the resistance of such a wire with a length of 24.0 m.
diameter, d = 2.05 mm
radius, r = 1.025 mm
Length, L = 24 m
resistivity of copper = 1.7 x 10^-8 ohm m
Let the resistance is R.