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fenix001 [56]
3 years ago
6

Two rods, one made of brass and the other made of copper, are joined end to end. The length of the brass section is 0.400 m and

the length of the copper section is 0.800 m . Each segment has cross-sectional area 0.00700 m2 . The free end of the brass segment is in boiling water and the free end of the copper segment is in an ice-water mixture, in both cases under normal atmospheric pressure. The sides of the rods are insulated so there is no heat loss to the surroundings.
(a) What is the temperature of the point where the brass and copper segments are joined?
(b) What mass of ice is melted in 5.00 min by the heat conducted by the composite rod?
Physics
1 answer:
vlabodo [156]3 years ago
7 0

Answer:

a) 36°

b) 0.109 kg

Explanation:

Heat flows from brass to copper with the brass having its temperature

Length of brass = 0.4

Length of copper = 0.8

Temperature of = 36.15

See attachment for calculation

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A)

Explanation:

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Block A of mass M is on a horizontal surface of negligible friction. An identical block B is attached to block A by a light stri
miv72 [106K]

Answer:

T’= 4/3 T  

The new tension is 4/3 = 1.33 of the previous tension the answer e

Explanation:

For this problem let's use Newton's second law applied to each body

Body A

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In the reference system we have selected the direction to the right as positive, therefore the downward movement is also positive. The acceleration of the two bodies must be the same so that the rope cannot tension

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We solve this system of equations

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    a = m_B / (m_A + m_B) g

In this initial case

     m_A = M

     m_B = M

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     a = ½ g

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Let's look for the relationship between the tensions of the two cases

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   T’/ T = 4/3

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The new tension is 4/3 = 1.33 of the previous tension the answer  e

4 0
3 years ago
What is the value of R2 in this parallel circuit? (5 stars)
o-na [289]

Answer:

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Answer:

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