Which piece of evidence justifies the sharing of information to form a scientific theory?

A constant force of 8.0 N is exerted for 4.0 s on a 16-kg object initially at rest. The change in speed of this object will be:

AfilCa [17]

The change in speed of this object is 3m/s

According to Newton's second law;

F = ma

F = mv/t

Given the following parameters

Force F = 8.0N

mass m = 16kg

time t = 4.0s

Required

speed v

Substitute the given parameters into the formula

v = Ft/m

v = 8 * 6/16

v = 48/16

v = 3m/s

Hence the change in speed of this object is 3m/s

Learn more here: brainly.com/question/19072061

8 0

2 years ago

Aloop of wire of area 71 cm^2 is placed with its plane parallel to a 16 mt magnetic field. the loop is then rotated so that its

kkurt [141]

Answer:

Approximately 1.62 × 10⁻⁴ V.

Explanation:

The average EMF in the coil is equal to

$\displaystyle \frac{\text{Final Magnetic Flux} - \text{Initial Magnetic Flux}}{2}$ ,

Why does this formula work?

By Faraday's Law of Induction, the EMF $\epsilon$ induced in a coil (one loop) is equal to the rate of change in the magnetic flux $\Phi$ through the coil.

$\displaystyle \epsilon(t) = \frac{d}{dt}(\Phi(t))$ .

Finding the average EMF in the coil is similar to finding the average velocity.

$\displaystyle \text{Average}\; \epsilon = \frac{1}{t}\int_0^t \epsilon(t)\cdot dt$ .

However, by the Fundamental Theorem of Calculus, integration reverts the action of differentiation. That is:

$\displaystyle \int_0^{t} \epsilon(t)\cdot dt = \int_0^{t} \frac{d}{dt}\Phi(t)\cdot dt = \Phi(t) - \Phi(0)$ .

Hence the equation

$\displaystyle \text{Average}\; \epsilon = \frac{1}{t}\int_0^t \epsilon(t)\cdot dt = \frac{\Phi(t)- \Phi(0)}{t}$ .

Note that information about the constant term in the original function will be lost. However, since this integral is a definite one, the constant term in $\Phi(t)$ won't matter.

Apply this formula to this question. Note that $\Phi$ , the magnetic flux through the coil, can be calculated with the equation

$\Phi = B \cdot A \cdot N \; \sin{\theta}$ .

For this question,

$B = \rm 16\; mT = 16\times 10^{-3}\; T$ is the strength of the magnetic field.
$A = \rm 71\; cm^{2} = 71\times \left(10^{-2}\right)^2 \; m^{2}$ is the area of the coil.
$N = 1$ is the number of loops in the coil.
$\theta$ is the angle between the field lines and the coil.
At $\rm 0\;s$ , the field lines are parallel to the coil, $\theta = 0^{\circ}$ .
At $\rm 0.7\; s$ , the field lines are perpendicular to the coil, $\displaystyle \theta = 90^{\circ}$ .

Initial flux: $\Phi(0)= 0$ .

Final flux: $\Phi(0.7) = \rm 1.1136\times 10^{-4}\; Wb$ .

Average EMF, which is the same as the average rate of change in flux:

$\displaystyle \frac{\Phi(0.7) - \Phi(0)}{0.7} \approx\rm 1.62\times 10^{-4}\; V$ .

8 0

3 years ago

_____________ forces are always attractive and the mass of an object determines how strong the ____________ pull is.

dolphi86 [110]

Gravitational, gravitational ! both the option are same

6 0

3 years ago

Which one should be my pfp?

Zepler [3.9K]

Explanation:

I think the third one coz it's so good

7 0

2 years ago

Read 2 more answers

Plz help me it’s a true or false question A shorter wire will allow electricity to

mr Goodwill [35]

-- A shorter wire will allow electricity to move through at a higher rate than a longer wire . . . True, but "rate" is a poor way to say it. It should say "a higher current".

-- A short, thick, cold wire is the best conductor . . . True

-- How well a material conducts current is an internal factor affecting resistance . . . True

-- If you double the length of a wire, you cut the resistance in half . . . False. Double the length also means double the resistance.

-- If you double the thickness of a wire, you cut the resistance in half . . . True

-- Superconductors have no measurable resistance . . . True. They literally have NO resistance.

-- The higher the temperature of the conductor, the lower the resistance . . . False. Higher temperature means higher resistance, for almost all conductors.

-- The resistance in a wire with less thickness is less . . . False. We just said, up above in Question-#5, "If you double the thickness of a wire, you cut the resistance in half". Less thickness means more resistance. Just like a highway with fewer lanes.

-- Thickness, length, and temperature are internal factors that affect resistance . . . False. They affect resistance, but they're external factors.

-- When a light is first switched on the light bulb's filament has a lower resistance than after it gives off light for awhile . . . True. Look back 3 questions from here, where it says "Higher temperature means higher resistance".

3 0

3 years ago