Answer:
are you college ?????????
The final velocity of the passenger is zero as he is brought to rest by the inflated bag.
Apply the equation of motion
Replacing with our values,
Calculate the force using the force equation,
Therefore the magnitude of force acts on the passenger's upper torso is 34.923kN
Answer:
6.34 x 19^14 Hz
Explanation:
Wavelength, λ = 473 nm = 473 x 10^-9 m
the relation between the frequency and the wavelength is given by
v = f x λ
where, v is the velocity of light in vacuum which is equal to 3 x 10^8 m/s.
So, f = v / λ
f = ( 3 x 10^8) / ( 473 x 10^-9)
f = 6.34 x 19^14 Hz
Answer:
C) 20 m/s
Explanation:
Wave: A wave is a disturbance that travels through a medium and transfers energy from one point to another, without causing any permanent displacement of the medium itself. Examples of wave are, water wave, sound wave, light rays, radio waves. etc.
The velocity of a moving wave is
v = λf ............................ Equation 1
Where v = speed of the wave, λ = wave length, f = frequency of the wave.
Given: f = 2 Hz (two complete cycles in one seconds), λ = 10 meters
Substituting these values into equation 1
v = 2×10
v = 20 m/s.
Thus the speed of the wave = 20 m/s
The right option is C) 20 m/s
Assuming ideal conditions, Boyle's law says that
<em>P₁ V₁ </em>= <em>P₂</em> <em>V₂</em>
where <em>P₁ </em>and <em>V₁</em> are the initial pressure and temperature, respectively, and <em>P₂</em> and <em>V₂</em> are the final pressure and temperature.
So you have
(455 mm Hg) (56.5 m³) = (632 mm Hg) <em>V₂</em>
==> <em>V₂</em> = (455 mm Hg) (56.5 m³) / (632 mm Hg) ≈ 40.7 m³
