(a) The power of the bulb is P=60.0 W. Half an hour corresponds to a time of
so the energy used by the bulb during this time is
(b) The efficiency of the bulb is 12%, it means that it converts only 12% of the input energy into thermal energy, so the thermal energy is
Answer:
Explanation:
Hello,
In this case, since the acceleration in terms of position is defined as its second derivative:
The purpose here is derive x(t) twice as follows:
Thus, the acceleration turns out 4.8 meters per squared seconds.
Best regards.
100 millimeters equals 0.1 meters.
The average acceleration of the car as it accelerates from 15 m/s to 25 m/s will be 2.5 m/s².
<h3>What is Average acceleration?</h3>
Average acceleration is the average rate of change of velocity with respect to time. Mathematically -
a = Δv/Δt
Given that a car is traveling at 15 m/s in north direction and in 4 seconds it accelerates to 25 m/s in the north direction only. Therefore, we can write -
initial velocity [u] = 15 m/s
final velocity [v] = 25 m/s
time taken [Δt] = 4 s
The magnitude of the average acceleration can be calculated as follows-
a = Δv/Δt
Δv = v - u = 25 - 15
Δv = 10 m/s
Therefore -
a = 10/4
a = 2.5 m/s².
Therefore, the average acceleration of the car will be 2.5 m/s².
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Answer:
Explanation:
A ) When gymnast is motionless , he is in equilibrium
T = mg
= 63 x 9.81
= 618.03 N
B )
When gymnast climbs up at a constant rate , he is still in equilibrium ie net force acting on it is zero as acceleration is zero.
T = mg
= 618.03 N
C ) If the gymnast climbs up the rope with an upward acceleration of magnitude 0.600 m/s2
Net force on it = T - mg , acting in upward direction
T - mg = m a
T = mg + m a
= m ( g + a )
= 63 ( 9.81 + .6)
= 655.83 N
D ) If the gymnast slides down the rope with a downward acceleration of magnitude 0.600 m/s2
Net force acting in downward direction
mg - T = ma
T = m ( g - a )
= 63 x ( 9.81 - .6 )
= 580.23 N