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2 years ago

What does the law of conservation of mass state?

Chemistry

1 answer:

dusya [7]2 years ago

6 0

Answer:

Explanation:

The law of conservation of mass states that the sum of the mass of the products equals the sum of the mass of the reactants. You cannot have a greater mass in the products or vice versa because mass cannot be created or destroyed.

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Craig needs to organize, analyze, and interpret large amounts of quantitative data that he generated during an experiment. Which

notsponge [240]

Answer:

C. a computer

Explanation:

Quantitative data are measures of values or counts and are expressed as numbers. The best tool out of all shown to deal with a large amount of numerical data is a computer

4 0

3 years ago

In a DNA sample, 15% of the bases are thymine (T). What percentage of the bases in this sample are cytosine (C)?

allochka39001 [22]

Answer:

C) 35%

Explanation:

Thymine pairs with adenine. If thymine is 15% then so would adenine be 15%. That leaves the reaminder to be 70%. Cytosine pairs with guanine, thereby, they would each be 35%.

3 0

3 years ago

Describe the structure of ammonium lauryl sulfate. Refer to the given diagram. Your answer should include the type of bonding, t

Anit [1.1K]

Answer:

The compound contains lauryl sulfate and ammoium ions. Lauryl sulfate contains lauric acid (in black and white) , the fatty acid formed by the covalent bonds between C-C attached to hydrogens, and sulfate ions attached to lauric acid (in red) with C-S covalent bond. Sulfer is attached to oxygen by covalent bonds. In Ammonium ions, N is surrounded by four hydrogen atoms.

6 0

3 years ago

How does government ensure a safe environment for inverters?

Anestetic [448]

hope it helps please brainliest

7 0

3 years ago

A compound containing Na, C, and O is found to have 1.06 mol Na, 0.528 mol C, and 1.59 mol O. What is the empirical formula of t

Effectus [21]

Given :

Moles of Na : 1.06

Moles of C : 0.528

Moles of O : 1.59

To Find :

The empirical formula of the compound.

Solution :

Dividing moles of each atom with the smallest one i.e 0.528 .

So,

Na : 1.06/0.528 = 2.007 ≈ 2

C : 0.528/0.528 = 1

O : 1.59/0.528 = 3.011 ≈ 3

Rounding all them to nearest integer, we will get the number of each atom in the empirical formula.

So, empirical formula is $Na_2CO_3$ .

Hence, this is the required solution.

5 0

3 years ago