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4 years ago

An object's weight is dependent upon its location in the universe. Why is this true?

Physics

2 answers:

solmaris [256]4 years ago

8 0

Explanation :

We know that the weight of an object is given by :

$W=mg$

Where,

m is the mass

g is the acceleration due to gravity.

The value of g changes from one location to another.

An object's weight is dependent upon its location in the universe. This statement is true. This is because g varies in different places so the weight also varies.

Hence, the correct option is (D) " This is true because weight is the magnitude of gravitational force acting on an object, and since gravitational force varies in different places in the universe, weight also varies ".

Bezzdna [24]4 years ago

6 0

Because an object's weight is the measure of the gravitational
forces between the object and other things that have mass.

In its travels around the universe, the object can be in the
neighborhood of other things with huge mass or tiny mass,
and it can be nearer to them or farther away from them. So
the gravitational forces between the object and other things
can have widely different values in different places.

Read the choices very carefully.
I think 'D' is the one that says this.

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How many wavelengths of a wave pass a point if the frequency of the wave is 4 hertz?

stepan [7]

Four of them pass a point every second.

3 0

3 years ago

An electric dipole is formed from ± 5.0 nC point charges spaced 3.0 mm apart. The dipole is centered at the origin, oriented alo

Ymorist [56]

Answer:

The electric field strength at point (x,y) = ( 20 mm ,0cm) is =16321.0769 N/C

The electric field strength at point (x,y) = (0cm, 20 mm) is =35321.58999 N/C

Explanation:

Question: What is the electric field strength at point (x,y) = ( 20 mm ,0cm)?

Answer:

The electric field at any given point of the dipole is given as:

E= (KP) ÷ (r^2 + a^2)^3/2

Where:

K = 9x10^9 Nm^2/c^2 (coloumb constant)

P = (0.003) (5x10^-9c) which is the movement of the dipole

(0.003) is arrived at when mm is converted to m. 3.0 mm space apart was converted to a meter.

r= the point, in the question above is 20mm = 0.02m

Now, the electric field, E can be calculated by putting the values in the formula above:

E = (KP) ÷ (r^2 + a^2)^3/2

= (9x10^9 Nm^2/c^2) (0.003 m) (5x10^-9c) ÷ [ (0.02m)^2 + (0.003)^2]^3/2

= 0.135 ÷ (8.271513x10^-6)

=16321.0769 N/C

Question: What is the electric field strength at point (x,y) = (0cm, 20 mm )?

Answer:

Here, the electric field, E= 2krp ÷ (r^2 - a^2)^2

E= 2 (9x10^9 Nm^2/c^2) (0.02m) (0.003 m) (5x10^-9c) ÷ [(0.02m)^2 - (0.003)^2]^2

= 0.0054 ÷ 0.000000152881

=35321.58999 N/C

8 0

3 years ago

Which two statements describe how ultrasound technology produces an image of a baby before it is born?

Elan Coil [88]

Answer:a and c

Explanation:

8 0

3 years ago

Read 2 more answers

What is the weight of a 4.2 kg bowling ball on Mars?

Nataliya [291]

What is the weight of a 4.2 kg bowling ball on Mars?

Answer:

1.59 kg

Explanation:

The formula is:

F = G((Mm)/r2)

F is the gravitational force between two objects,

G is the Gravitational Constant (6.674×10-11 Newtons x meters2 / kilograms2),

M is the planet's mass (kg),

m is your mass (kg), and

r is the distance (m) between the centers of the two masses (the planet's radius).

Hope this helps

--Jay

8 0

4 years ago

state and explain any effect on sensitivity of liquid in a glass thermometer (i) reducing the diameter of capillary tube

Ad libitum [116K]

Answer:

please give me brainlist and follow

Explanation:

The measuring sensitivity of liquid-in-glass thermometers increases with the amount of liquid in the thermometer. The more liquid there is, the more liquid will expand and rise in the glass tube. For this reason, liquid thermometers have a reservoir to increase the amount of liquid in the thermometer.

4 0

3 years ago