W = force * displacement
W = 32 pounds * 10 feet
Now you need to convert it to newton and meters
W = 142 N * 3.048 m = 434 J
(I approximated the conversions- I hope it helps)
The approximate lateral area of the prism is determined as 831 square inches.
<h3>
What is lateral area of the hexagonal prism?</h3>
The lateral area of the hexagonal prism is calculated as follows;
LA = PH
where;
- P is perimeter of the prism
- H is height
A = ¹/₂Pa
where;
- a is apothem = 10 inches
- A is base area = 346.41 in²
346.41 = ¹/₂(10)P
346.41 = 5P
P = 346.41/5
P = 69.282 inches
LA = PH
LA = 69.282 x 12
LA = 831.38 in²
Learn more about lateral area of prism here: brainly.com/question/296674
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Answer:
The tension in the rope is 262.88 N
Explanation:
Given:
Weight 
N
Length of rope 
m
Initial speed of ball 
For finding the tension in the rope,
First find the mass of rod,
( 
)
kg
Tension in the rope is,
N
Therefore, the tension in the rope is 262.88 N
Answer:
when an x-ray passes trough matter, it undergoes a process called attenuation
The answer is diffraction or interference
