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Nat2105 [25]
3 years ago
8

If an antelope can run 14.1 km in 39 min, how fast is it km/h(for reference , 110 km/h is 65 mph )

Physics
2 answers:
shtirl [24]3 years ago
8 0
It might make more sense putting it another way but this is basically it. you just take the minutes and divide them by 60 to convert them to hours. then simplify the ratio

adelina 88 [10]3 years ago
3 0
Should be 21.7 km/hr. Convert minutes to hours by dividing 39/60. then divide 14.1 by .65 which is 39 minutes converted to hours.
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A force of 7 N acts on an object. The displacement is, say 8 m, in the direction of the force. Let us take it that the force act
MA_775_DIABLO [31]

Answer:

cos 0 = 1.

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Explanation:

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What is the equation describing the motion of a mass on the end of a spring which is stretched 8.8 cm from equilibrium and then
Sedbober [7]

Answer:

x=(0.088m)\cos(\sqrt{\frac{k}{m} }  t)

Explanation:

We first identify the elements of this simple harmonic motion:

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The angular frequency ω can be calculated with the formula:

\omega =\sqrt{\frac{k}{m}}

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Finally, the equation of the motion of the system is:

x=(0.088m)\cos(\omega t)

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A charge Q is uniformly spread over one surface of a very large nonconducting square elastic sheet having sides of length d. At
GuDViN [60]

Answer:

E/4

Explanation:

The formula for electric field of a very large (essentially infinitely large) plane of charge is given by:

E = σ/(2ε₀)

Where;

E is the electric field

σ is the surface charge density

ε₀ is the electric constant.

Formula to calculate σ is;

σ = Q/A

Where;

Q is the total charge of the sheet

A is the sheet's area.

We are told the elastic sheet is a square with a side length as d, thus ;

A = d²

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σ = Q/d²

Putting Q/d² for σ in the electric field equation to obtain;

E = Q/(2ε₀d²)

Now, we can see that E is inversely proportional to the square of d i.e.

E ∝ 1/d²

The electric field at P has some magnitude E. We now double the side length of the sheet to 2L while keeping the same amount of charge Q distributed over the sheet.

From the relationship of E with d, the magnitude of electric field at P will now have a quarter of its original magnitude which is;

E_new = E/4

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3 years ago
5. What is the total length of the path of travel fron start of motion to the final place?
hodyreva [135]
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