The attraction of an object to something else with mass. What is the solar
system? The solar system is the alignment of planets around the sun. All the planets are in orbit around the sun. Our Solar System There are also Asteroids, comets, moons, and other forms of matter throughout space So What is the major role of gravity in our solar system? Holding Everything In Place. Without gravity a lot of things
<span>would go wrong. If there was no gravitational force on planets, people would float off into the sky.</span>
Hello there.
<span>In the context of depth perception, which of the following is a monocular cue?
</span><span>(C) Convergence
</span>
Answer:
a) 2.87 m/s
b) 3.23 m/s
Explanation:
The avergare velocity can be found dividing the length traveled d by the total time t.
a)
For the first part we easily know the total traveled length which is:
d = 50.2 m + 50.2 m = 100.4 m
The time can be found dividing the distance by the velocity:
t1 = 50.2 m / 2.21 m/s = 22.7149 s
t2 = 50.2 m / 4.11 m/s = 12.2141 s
t = t1 +t2 = 34.9290 s
Therefore, the average velocity is:
v = d/t =2.87 m/s
b)
Here we can easily know the total time:
t = 1 min + 1.16 min = 129.6 s
Now the distance wil be found multiplying each velocity by the time it has travelled:
d1 = 2.21 m/s * 60 s = 132.6 m
d2 = 4.11 m/s *(1.16 * 60 s) = 286.056 m
d = 418.656 m
Therefore, the average velocity is:
v = d/t =3.23 m/s
Answer:
51.94°
Explanation:
= Unpolarized light
= Light after passing though second filter = ![0.19I_0](https://tex.z-dn.net/?f=0.19I_0)
Polarized light passing through first filter
![I_1=\frac{I_0}{2}](https://tex.z-dn.net/?f=I_1%3D%5Cfrac%7BI_0%7D%7B2%7D)
Polarized light passing through second filter
![I_2=\frac{I_0}{2}cos^2\theta\\\Rightarrow 0.19I_0=\frac{I_0}{2}cos^2\theta\\\Rightarrow cos^2\theta=\frac{0.19I_0}{\frac{I_0}{2}}\\\Rightarrow cos\theta=\sqrt{\frac{0.19I_0}{\frac{I_0}{2}}}\\\Rightarrow \theta=cos^{-1}\sqrt{\frac{0.19I_0}{\frac{I_0}{2}}}\\\Rightarrow \theta=cos^{-1}\sqrt{0.19\times 2}\\\Rightarrow \theta=cos^{-1}\sqrt{0.38}\\\Rightarrow \theta=51.94^{\circ}](https://tex.z-dn.net/?f=I_2%3D%5Cfrac%7BI_0%7D%7B2%7Dcos%5E2%5Ctheta%5C%5C%5CRightarrow%200.19I_0%3D%5Cfrac%7BI_0%7D%7B2%7Dcos%5E2%5Ctheta%5C%5C%5CRightarrow%20cos%5E2%5Ctheta%3D%5Cfrac%7B0.19I_0%7D%7B%5Cfrac%7BI_0%7D%7B2%7D%7D%5C%5C%5CRightarrow%20cos%5Ctheta%3D%5Csqrt%7B%5Cfrac%7B0.19I_0%7D%7B%5Cfrac%7BI_0%7D%7B2%7D%7D%7D%5C%5C%5CRightarrow%20%5Ctheta%3Dcos%5E%7B-1%7D%5Csqrt%7B%5Cfrac%7B0.19I_0%7D%7B%5Cfrac%7BI_0%7D%7B2%7D%7D%7D%5C%5C%5CRightarrow%20%5Ctheta%3Dcos%5E%7B-1%7D%5Csqrt%7B0.19%5Ctimes%202%7D%5C%5C%5CRightarrow%20%5Ctheta%3Dcos%5E%7B-1%7D%5Csqrt%7B0.38%7D%5C%5C%5CRightarrow%20%5Ctheta%3D51.94%5E%7B%5Ccirc%7D)
The angle between the two filters is 51.94°