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3 years ago

What is newtons law?

1 answer:

8 0

When considering newtons laws, we would understand that this would first, be when, a object is at rest, it remains at rest, when a object is at speed, it remains in speed, unless there were to be a object to go against it. This would just be an example if one of his laws.

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5 problem associated with PopulationCensus

dolphi86 [110]

Answer:

1. High Illiteracy Rate in a Nation has a Negative Impact on the Conducting of Census

2.Corruption Interferes with Census

3.Traditional and Religious Beliefs can Interfere with the Census Exercise

4.insufficient and Ineffective Census Educational Campaign

5.Insufficient Census Experts

Explanation:

5 0

4 years ago

When the light from the sun warms the ground, the transfer of energy of heat is called...

NISA [10]

C. Radiation Hope this helps and You're welcome. :3

3 0

3 years ago

Read 2 more answers

Rotational dynamics about a fixed axis: A person pushes on a small doorknob with a force of 5.00 N perpendicular to the surface

FrozenT [24]

Answer:

I = 2 kgm^2

Explanation:

In order to calculate the moment of inertia of the door, about the hinges, you use the following formula:

$\tau=I\alpha$ (1)

I: moment of inertia of the door

α: angular acceleration of the door = 2.00 rad/s^2

τ: torque exerted on the door

You can calculate the torque by using the information about the Force exerted on the door, and the distance to the hinges. You use the following formula:

$\tau=Fd$ (2)

F: force = 5.00 N

d: distance to the hinges = 0.800 m

You replace the equation (2) into the equation (1), and you solve for α:

$Fd=I\alpha\\\\I=\frac{Fd}{\alpha}$

Finally, you replace the values of all parameters in the previous equation for I:

$I=\frac{(5.00N)(0.800m)}{2.00rad/s^2}=2kgm^2$

The moment of inertia of the door around the hinges is 2 kgm^2

3 0

4 years ago

What happens to the mass and volume if density increases

nikitadnepr [17]

They all stay the same regardless

7 0

4 years ago

A wire that is 0.86 meters long is moved perpendicularly through a constant magnetic field of strength 0.035 newtons/amp·meter a

GaryK [48]

The emf induced = B*l*v where B is the flux density, l the length of the conductor and v the velocity of the conductor. In the given case B = 0.035 N/amp.meter, l = 0.86 and v = 6 m/sec
emf = 0.035*0.86*6 = 0.1806 v ≈ 0.18 v
choice: D

6 0

3 years ago