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1 year ago

After fertilization in the fallopian tube, how many days will the zygote travel before arriving at uterus?.

1 answer:

6 0

After fertilization in the fallopian tube, It will take 6-12 days for the zygote to travel before arriving at the uterus.

<h3>What is a zygote?</h3>

A zygote is, generally speaking, a cell created by the fusion of two gametes; the growing person is created from such a cell.

It takes the zygote around 6–12 days following fertilization in the fallopian tube for the fertilized egg to travel to the uterus and attach to the uterus, a process known as implantation.

Hence It will take 6-12 days for the zygote to travel before arriving at the uterus.

To learn more about the zygote refer;

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The flywheel in the shape of a solid cylinder of mass 75.0 kg and diameter 1.40 m rotates about an axis passing through the cent

Anni [7]

The torque required for the cylinder is 76.99 N m.

What is torque?

Torque may be defined as the product of the force and the distance perpendicular to the force from the axis of rotation.

Calculation of the angular acceleration:

The first kinematic equation for the rotational motion is,

ω=ω₀+αt

where ω₀ is the initial angular velocity, ω is the final angular velocity, α is the angular acceleration and t is the time. Since the cylinder starts from the rest, its initial angular velocity is zero.

Here, ω=320 rev/min or ω=320*2π/60 rad/sec, ω₀=0 and t=8.00 sec. Put these values in the above equation and solve it to get the value of angular acceleration.

320*2π/60=0+α*8

α=320*2π/(8*60)

α=4.19 rad/s^2

Calculation of the torque:

The torque T is given by the formula,

T=Iα

where I is the moment of inertia.

For the cylinder, I=1/2*mr^2

where m is the mass of the cylinder and r is the radius of the cylinder.

So,

T=1/2*mr^2*α

Here m=75 kg, radius r is half of the diameter r=1.4/2=0.7 m, and α=4.19 rad/s^2. Using these values in the formula of torque.

T=1/2*(75)*(0.7)^2*4.19

T= 76.99 N m

Learn more about the torque.

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6 0

1 year ago

A piece of plastic has a net charge of +9.9 μC. How many more protons than electrons does this piece of plastic have? (e = 1.60

Leto [7]

Answer:

The number of protons 6.19 more than electron.

Explanation:

Given that,

Charge $Q=+9.9\times10^{-6}\ C$

We know that,

formula of charge

$Q = nc$

Where,

Q = total charge

n = number of protons

e = charge of electron

Put the value into the formula

$n = \dfrac{Q}{e}$

$n=\dfrac{9.9\times10^{-6}}{1.6\times10^{-19}}$

$n=6.1875\times10^{13}\ C$

According to statement of question

Divide the answer by $10^{13}$

$n=\dfrac{6.1875\times10^{13}}{10^{13}}$

$n=6.19\ C$

Hence, The number of protons 6.19 more than electron.

6 0

2 years ago

Pepe and Alfredo are resting on an offshore raft after a swim. They estimate that 3.0 m separates a trough and an adjacent crest

Agata [3.3K]

Answer:

The velocity ( $v$ ) of the wave is 3.08 $ms^{-1}$ .

Explanation:

According to the figure, the distance ( $\large{L}$ ) between a trough and its adjacent crest is $\large{L = 3 m}$ . Also the wavelength ( $\large{\lambda}$ ) of the wave is $\large{\lambda = 2L}$ . Pepe and Alfredo count 11 crests to pass the raft in $\large{t}$ = 21.5 s.

So, the time period ( $\large{T}$ ) of oscillation of the wave is

$\large{T} = \dfrac{t}{11} = \dfrac{21.5}{11} = 1.95s$

So, the velocity ( $\large{V}$ ) of the wave is

$\large{V = \dfrac{\lambda}{T} = \dfrac{2 \times L}{T} = \dfrac{2 \times 3}{1.95}= 3.08 ms^{-1}}$

4 0

2 years ago

What are the density, specific gravity and mass of the air in a room whose dimensions are 4 m * 6 m * 8 m at 100 kPa and 25 C.

Volgvan

Answer:

Density = 1.1839 kg/m³

Mass = 227.3088 kg

Specific Gravity = 0.00118746 kg/m³

Explanation:

Room dimensions are 4 m, 6 m & 8 m. Thus, volume = 4 × 6 × 8 = 192 m³

Now, from tables, density of air at 25°C is 1.1839 kg/m³

Now formula for density is;

ρ = mass(m)/volume(v)

Plugging in the relevant values to give;

1.1839 = m/192

m = 227.3088 kg

Formula for specific gravity of air is;

S.G_air = density of air/density of water

From tables, density of water at 25°C is 997 kg/m³

S.G_air = 1.1839/997 = 0.00118746 kg/m³

4 0

3 years ago

When you stop at a railroad crossing at night, instead of correctly perceiving two red lights that flash alternately you may per

Nezavi [6.7K]

I'm pretty sure that there should be an options to choose. Anyway, I've seen this question before and I know that this is an example of <span>the phi phenomenon.</span>

7 0

3 years ago

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