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Vlada [557]
2 years ago
11

After fertilization in the fallopian tube, how many days will the zygote travel before arriving at uterus?.

Physics
1 answer:
natta225 [31]2 years ago
6 0

After fertilization in the fallopian tube, It will take 6-12 days for the zygote to travel before arriving at the uterus.

<h3>What is a zygote?</h3>

A zygote is, generally speaking, a cell created by the fusion of two gametes; the growing person is created from such a cell.

It takes the zygote around 6–12 days following fertilization in the fallopian tube for the fertilized egg to travel to the uterus and attach to the uterus, a process known as implantation.

Hence It will take 6-12 days for the zygote to travel before arriving at the uterus.

To learn more about the zygote refer;

brainly.com/question/465851

#SPJ1

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A wooden block meauring 40cm x 10cm x 5cm has a mass 850gm . find the density of wood?
Lelechka [254]

Answer:

Explanation:

Density = Mass / Volume = 850 / 40*10*5 = 0.425 g /cm^3

5 0
3 years ago
7. A mother pushes her 9.5 kg baby in her 5kg baby carriage over the grass with a force of 110N @ an angle
jasenka [17]

Weight of the carriage =(m+M)g =142.1\ N

Normal force =Fsin(\theta) + W = 197.1\ N

Frictional force =\mu N=27.59\ N

Acceleration =4.66\ m\ s^{-2}

Explanation:

We have to look into the FBD of the carriage.

Horizontal forces and Vertical forces separately.

To calculate Weight we know that both the mass of the baby and the carriage will be added.

  • So Weight(W) =(m+M)\times g =(9.5+5)\ kg \times 9.8 =142.1\ Newton\ (N)

To calculate normal force we have to look upon the vertical component of forces, as Normal force is acting vertically.We have weight which is a downward force along with F_x, force of 110\ N acting vertically downward.Both are downward and Normal is upward so Normal force =Summation\ of\ both\ forces

  • Normal force (N) = Fsin(\theta)+W=110sin(30) + 142.1 =197.1\ N
  • Frictional force (f) =\mu N=0.14\times 197.1 =27.59\ N

To calculate acceleration we will use Newtons second law.

That is Force is product of mass and acceleration.

We can see in the diagram that F_y=Horizontal and F_x=Vertical component of forces.

So Fnet = Fy(Horizontal) - f(friction) = m\times a

  • Acceleration (a) =\frac{Fcos(\theta)-\mu N}{mass(m)} =\frac{(95.26-27.59)}{14.5}= 4.66\ m\ s{^2 }

So we have the weight of the carriage, normal force,frictional force and acceleration.

3 0
2 years ago
what are the 3 properties of components of the universe that can be determined using electromagnetic radiation?
stepan [7]
Your answer is electricity, light and magnetism.  They can be determined usinf elecromagnetic radioation. 
<span>
Even the energy  can't be detected by our eyes, there are a lot of measurement  instruments that can measure infrared (IR), gamma rays, radio or X-rays or ultraviolet (UV)</span>
4 0
3 years ago
A room has a wall with an R value of 18 F sq.ft. hr/BTU. The room is 15 feet long and 11 feet wide with walls that are 9 ft high
seropon [69]

Answer:

The heat transferred through the wall that day is  13728 BTUs

Explanation:

Here, we have the area of the wall given as

Area of wall = 2 × Length × Height + 2 × Width × Height

Length = 15 feet

Width = 11 Feet and

Height = 9 feet

Therefore, the area = 2×15×9 + 2×11×9 = 468 ft²

Temperature difference is given by

Average outside temperature - Wall temperature = 40 - 18 = 22 °F

Therefore the heat transferred through the wall that day (24 hours) at 18 sq.ft. hr/BTU is given by;

468 × 22 × 24/18 = 13728 = 13728 BTUs.

5 0
3 years ago
Un avión vuela a 10000m de altura y otro a 33300 pies, si un pie equivale a 30.48cm ¿Cuál vuela a mayor altura?
user100 [1]

Answer:

Avion A (10000 meters).

Explanation:

Deje que la altura de los aviones sea A y B respectivamente.

Dados los siguientes datos;

Altura A = 10000 metros

Altura B = 33300 pies

Para encontrar el avión que voló más alto, tendríamos que hacer alguna conversión de unidades.

Conversión:

Metros a centímetros;

1 metro = 100 cm

10000 metros = 100 * 10000 = 1.000.000 centímetros.

Por lo tanto, la altura A en cm = 1,000,000 centímetros

Pies a centímetros;

1 pie = 30,48 centímetros

33300 pies = 33300 * 30,48 = 1014984 centímetros.

Por lo tanto, la altura B en cm = 1014984 centímetros.

De los cálculos anteriores, podemos deducir que el avión A voló más alto.

6 0
3 years ago
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