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3 years ago

A hiker walks with an average speed of 2.6 M Square what distance in kilometers does the hiker travel in a time of 2.8 hours

Physics

1 answer:

solmaris [256]3 years ago

5 0

Answer:

The answer is "26.208 km"

Explanation:

Given value:

$\to S= 2.6 \ \frac{m}{s}\\\\\to t= 2.8 \ hours$

Formula:

$d= st\\\\d= 2.6 \times 2.8 \times \frac{60 \times 60}{1000}\\\\d= 26.208\ km$

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Svet_ta [14]

Answer:

See below ~

Explanation:

An object will sink in water when its density is greater than that of water, which is 1 g/cm³.

Volume of the box is 1331 cm³. (11³)

Maximum mass of sand will be 1331 g. [because 1331/1331 = 1 g/cm³]

Volume of sand = Mass of sand / Density of sand
Volume (sand) = 1331/3.5
Volume (sand) = 380.29 cm³

If the volume of sand is greater than 380.29 cm³, the box will sink in water.

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2 years ago

Help me find the acceleration

ANEK [815]

a = 3.09 m/s²

<h3>Explanation</h3>

This question doesn't tell anything about how long it took for the car to go through 105 meters. As a result, the timeless suvat equation is likely what you need for this question.

In the timeless suvat equation,

$a = \dfrac{v^2 - u^2}{2\; x}$

where

$a$ is the acceleration of the car;
$v$ is the final velocity of the car;
$u$ is the initial velocity of the car; and
$x$ is the displacement of the car.

Note that v and u are velocities. Make sure that you include their signs in the calculation.

In this question,

$a$ is the unknown;
$v = -10.9 \; \text{m} \cdot \text{s}^{-2}$ ;
$u = -27.7 \; \text{m} \cdot \text{s}^{-2}$ ; and
$x = - 105 \; \text{m}$ .

Apply the timeless suvat equation:

$a = \dfrac{v^{2} - u^{2}}{2\; x}\\\phantom{a} = \dfrac{(-10.9)^{2} - (-27.7)^{2}}{2 \times (-105)}\\\phantom{a} = 3.09 \; \text{m} \cdot \text{s}^{-2}$ .

The value of $a$ is greater than zero, which is reasonable. Velocity of the car is negative, meaning that the car is moving backward. The car now moves to the back at a slower speed. Effectively it accelerates to the front. Its acceleration shall thus be positive.

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3 years ago

8. What is the momentum of a 120-kg professional fullback running across the line at 11.2 m/s?

Alchen [17]

Answer:

134r kgm^-1 or 1344 kg /m

Explanation:

Momentum is is given by:

p=mv

Where:

p is momentum, m is mass in kg and v is velocity in ms−1

p=120kg×11.2 m/ s= 1344 kgms=1344kgm^−1

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2 years ago

What is the mode of 3, 9, 11, 11, 3, 6, 2, 2, 11? 0 11 2 5,5

hodyreva [135]

Answer:11

Explanation: because is the number that repeted 2 times

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3 years ago

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Which of the following substance is not formed by chemical bonds? A.) Mixture

Rudiy27

The answer to your question would be C

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2 years ago