Answer:
a) P' = P_original, b) P ’= P_original + ρ g Δh
Explanation:
The expression for nanometric pressure is
P = ρ g h
where ρ is the density of the liquid and h is the height
a) we change the radius of the barrel, but keeping the same height
as the pressure does not depend on the radius it remains the same
P' = P_original
b) We change the barrel height
h ’≠ h
we substitute in the equation
P ’= ρ g h’
h ’= h + Δh
P ’= ρ g (h + Δh)
P ’= (ρ g h) + ρ g Δh
P ’= P_original + ΔP
In this case, the pressure changes due to the new height,
*if it is higher than the initial one, the pressure increases
*if the height is less than the initial one, the pressure is less
Whenever the motion of an object <em><u>changes</u></em> . . . speeding up, or slowing down,
or changing direction . . . that change is called "<em><u>acceleration</u></em>". Acceleration is
produced by force on the object.
If there is <em><u>no force</u></em> on the object, then there is no acceleration. That means that
its motion <em><u>doesn't change</u></em>. The object remains in constant, uniform motion ...
moving with steady speed, in a straight line.
No force is necessary to <em><u>keep</u></em> an object moving, only to <em><u>change</u></em> its motion.
12.
Because why calculating displacement you only take two points in time, in this situation being the initial position and the final position. The distance between these two points is 12 kilometers.
