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Inessa [10]
3 years ago
10

why is it much easier for group 14 elements to become stable by sharing instead of transferring electrons9

Chemistry
2 answers:
Effectus [21]3 years ago
5 0

Because they are closer to the farther end of the periodic table. Since they are closer to the farther end they don't want to give away their electrons because it would be easier for them to just steal them from other atoms.

Anvisha [2.4K]3 years ago
5 0

Answer:

Because of their intermediate electronegativity

Explanation:

First of all, any element of the periodic table interacts with other atoms to complete the octet in its last atomic level and achive stability, either losing or gaining electrons.  

Group 14 elements have 4 electrons in the last level, so it would seem that for they its the same to lose or gain electrons. But actually its neither, for them is easier to share the electrons with other atoms.

This is because they don't have a <u>very high electronegativity</u> (making them able to steal electrons) nor a <u>very low electronegtivity </u>(making them anle to release electrons).

This intermediate electronegativity is the responsable of the sharing of electrons.

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EXTRA CREDIT
marin [14]

Answer:

\huge\boxed{\sf 36\ H\ atoms}

Explanation:

<u>Molecular formula from Glucose:</u>

C₆H₁₂O₆

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3C₆H₁₂O₆

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\rule[225]{225}{2}

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2 years ago
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Read 2 more answers
If copper carbonate system is heated for too short a time, what will you notice for mass percent of copper be too large or too s
sammy [17]

Answer:

The mass percent of copper as element is the same.

Explanation:

First of all we need the reaction that is presented below:

CuCO_{3 (s)} +Heat → CuO_{(s)} + CO_{2 (g)}

The mass percent of copper (Cu) as element is the same because of during the reaction the element only transform its nature from copper carbonate (CuCO_{3 (s)}) to copper oxide (CuO_{(s)}), the latter is a solid and will remain in the system.

On the other hand, you will note that the global percentage mass will be small because of the reaction produce (CO_{2 (g)}) that is a gas and this one will escape for the system.  

Have a great day!

3 0
3 years ago
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