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3 years ago

What is the value of 5 ^ 3 * i ^ 9

Mathematics

1 answer:

leva [86]3 years ago

7 0

Answer:

Step-by-step explanation:

5 ^ 3 = 5 * 5 *5 = 125

i⁹ = i⁴ * i⁴ * i = 1 * 1 * i = i

5 ^ 3 * i ^ 9 = 125 * i = 125i

5 ^ 3 * i ^ 9

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oksano4ka [1.4K]

Answer:

Step-by-step explanation:

divide 20 by four

20/4=5/1

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10/15=2/3

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2 years ago

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Mars2501 [29]

Answer:

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Step-by-step explanation:

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3 years ago

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antiseptic1488 [7]

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3 years ago

A mixture of compounds X and Y in a 0.100-cm cell had an absorbance of 0.215 at 272 nm and 0.191 at 327 nm. Find [X] and [Y] in

Oksi-84 [34.3K]

Answer: The concentration of X is $7.13582\times 10^{-6}$ and the concentration of Y is $2.53159\times 10^{-5}$ .

Step-by-step explanation:

Since we have given that

At 272 nm, absorbance = 0.215

At 327 nm, absorbance = 0.191

As we have given that

Compound X Compound Y

272 16400 3870

327 3990 6420

So, our equations becomes

$16400C_1+3870c_2=0.215\\\\3990C_1+6420C_2=0.191$

By solving these two equations, we get that

$C_1=7.13582\times 10^{-6}\\\\C_2=2.53159\times 10^{-5}$

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4 years ago