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3 years ago

Rank these real gases according to how closely they resemble an ideal gas. CO, N2, Ne, He, NH3

Chemistry

1 answer:

Gemiola [76]3 years ago

8 0

He is the closest. Then:

Ne, N2, CO, NH3.

NH3 is the least closest to ideal.

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What is the volume of an irregular object if the initial volume in the graduated cylinder is 3.50 ml and it rises to 7.50 ml aft

Margarita [4]

Answer is: the volume of an irregular object is 4,00 ml.
Volume is the amount of space the object occupies and can be finded immersing it in water in a container with volume markings and than see how much the level of the container changes (goes up).
V(irregular object) = V(final volume) - V(initial volume).
V(irregular object) = 7,50 ml - 3,50 ml.
V(irregular object) = 4,00 ml.

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3 years ago

If you start with 10ml of 0.75 m cu(no3)2 how much cu (s) in grams should be recovered in step #7

LenaWriter [7]

0.48 grams. Not a well worded question since it's assuming I know the reactions. But I'll assume that since there's just 1 atom of copper per molecule of Cu(NO3)2, that the reaction will result in 1 atom of copper per molecule of Cu(NO3)2 used. With that in mind, we will have 0.010 l * 0.75 mol/l = 0.0075 moles of copper produced. To convert the amount in moles, multiply by the atomic weight of copper, which is 63.546 g/mol. So 0.0075 mol * 63.546 g/mol = 0.476595 g. Round the results to 2 significant figures, giving 0.48 grams.

4 0

3 years ago

If a dog has a mass of 16.1 kg, what is its mass in the following units? Use scientific notation in all of your answers.

nekit [7.7K]

Answer:

$16.1\times 10^3\ \text{g}$

$16.1\times 10^{6}\ \text{mg}$

$16.1\times 10^{9}\ \mu\text{g}$

Explanation:

Mass of dog = $16.1\ \text{kg}$

$1\ \text{kg}=10^{3}\ \text{g}$

$1\ \text{kg}=10^{6}\ \text{mg}$

$1\ \text{kg}=10^{9}\ \mu\text{g}$

So,

$16.1\ \text{kg}=16.1\times 10^3\ \text{g}$

$16.1\ \text{kg}=16.1\times 10^{6}\ \text{mg}$

$16.1\ \text{kg}=16.1\times 10^{9}\ \mu\text{g}$

Mass of the dog in the other units is $16.1\times 10^3\ \text{g}$ , $16.1\times 10^{6}\ \text{mg}$ and $16.1\times 10^{9}\ \mu\text{g}$ .

3 0

2 years ago

1.00g of a metallic element reacts completely with 300cm3 of oxygen at 298K and 1 atm pressure to form an oxide which contains O

elena55 [62]

Answer:

The metal is most likely calcium which has a molar mass of 40.078 g

Note: The question is incomplete. The complete question is given below:

1.00g of a metallic element reacts completely with 300cm3 of oxygen at 298K and 1 atm pressure to form an oxide which contains O2– ions. The volume of one mole of gas at this temperature and pressure is 24.0dm3 .

What could be the identity of the metal?

A calcium B magnesium C potassium D sodium

Explanation:

Number of moles of the oxygen gas reacted is first determined:

Volume of oxygen gas = 300 cm³ = 0.30 dm³

1 mole of a gas occupies 24.0 dm³ at this temperature and pressure

Number of moles of oxygen gas that will occupy 0.30 dm³ = 0.3/24 = 0.125 moles

Let M be represent the metallic element. The equation of the reaction will be:

2M + O₂ ----> 2MO

From the equation of reaction;

2 moles of the metal reacts with 1 mole of oxygen gas

2 * 0.125 moles of the metal will react with 300 cm³ of oxygen = 0.025 moles

Since the mass of the metal that reacted with oxygen is 1.0 g, therefore, 1.0 g of the metal = 0.025 moles

mass of 1 mole of the metal = 1 /0.025 = 40.0 g

Therefore, the metal is most likely calcium which has a molar mass of 40.078 g

5 0

2 years ago

I need to figure out what the unit to measure time is

Lady_Fox [76]

Measure time by seconds.

4 0

3 years ago