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Hoochie [10]
4 years ago
6

A measure of how far an object has moved from a starting point

Physics
1 answer:
Anvisha [2.4K]4 years ago
5 0
Volume??? velocity??????
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A brick is released with no initial speed from the roof of a building and strikes the ground in 2.50 s, encountering no apprecia
Elenna [48]

Answer:A brick is released with no initial speed from the roof of a building and strikes the ground in 2.50 s, encountering no ..

6 0
2 years ago
Which of the following are true about a "simple compressible system"? It cannot be a mixture of different substances (e.g. oxyge
fomenos

Explanation:

The volume of a simple compressible system is not fixed. At a state of equilibrium, there should be uniformity in the entire system.

From the question we have here, these are the correct options:

1. It cannot be a mixture of different substances (e.g. oxygen and nitrogent)

2. It can be composed of any phases of a substance: solid, liquid, and/or gas

3. It's state is specified if given two independent, intensive thermodynamic properties.

4 0
3 years ago
Which statement did Ernest Rutherford make about atoms?
PtichkaEL [24]

Answer:

Option A

Explanation:

Ernest Rutherford concluded that the atom has a small, dense center which constitutes the mass of the whole atom. He called it a "Nucleus". He also said that most of the space in the atom is empty.

6 0
3 years ago
How does inertia affect a person who is not wearing a seatbelt during a collision?
irina [24]
En caso de una colisión de bajo nivel de gravedad podría golpearse con el tablero del carro o en la parte del sillón (si esta sentado en la parte trasera). Pero si es muy grave la colisión podría salirse del carro por el cristal.
7 0
4 years ago
Read 2 more answers
A bungee jumper of mass m jumps off a bridge. Assume that the bungee cord behaves like am ideal spring of spring constant k. Whe
DanielleElmas [232]

Answer:

b) √[(kx²/m) - 2gx]

Explanation:

The energy at the lowest point is equal to:

E_{elas}=\frac{1}{2} *k*x^{2}

where:

Eelas = elastic energy [J]

k = spring constant [N/m]

x = extension of the spring [m]

We consider the lowest point, as the point where the potential energy is zero. At the moment when the person goes back through the point of the normal length of the elastic cord, it is this point that the person will have potential energy and kinetic energy.

E_{elas}=E_{pot}+E_{kine}\

\frac{1}{2}*k*x^{2}=m*g*x +\frac{1}{2} *m*v^{2}  \\v^{2} = \frac{k*x^{2} }{m}-2*g*x\\ v=\sqrt{\frac{k*x^{2} }{m}-2*g*x}

8 0
3 years ago
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