Answer: a= 4.4ms-2
Displacement= 26.95 m
Explanation:
First, the speed in km/hr must be converted to m/s so that we can apply it in solving the question. The motion started from rest hence the initial velocity is 0m/s. The average displacement is also obtained from the equations of motion as shown in the image attached.
Answer:
A . Are the masses repelling or attracting
answer:
<em><u>So, positive energy densities ("masses") attract each other by gravitational interaction. This is the general idea.</u></em>
<em><u>B</u></em>. What is the magnitude of the electrical force between the objects<em><u>?</u></em>
<em><u>answer</u></em><em><u>:</u></em>
<em><u> </u></em><em><u>The magnitude of the electrostatic force F between two point charges q1 and q2 is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them.</u></em>
C. What would the magnitude of the force be if one of the charges was 1/3 the amount?
answer:
<em><u>0.45</u></em>
D. ) What would the force be if the distance between the charges was only 1 meter (with the original charges)?
answer;
<em><u>Fmin=2.3×10^−28</u></em><em><u>N</u></em>
<em><u>E</u></em><em><u>:</u></em><em><u> </u></em>What would the force be if one of the charges was 1/3 the amount AND the distance was 1 meter?
answer;
<em><u>Electrostatic force is directly related to the charge of each object. So if the charge of one object is doubled, then the force will become two times greater.</u></em>
<em><u>#</u></em><em><u>CARRYONLEARNING</u></em><em><u>:</u></em><em><u>)</u></em>
<em><u>LOVEUALL</u></em>
(20 seconds / 40 vibes) = (20/40) (seconds/vibe) = 0.5 second
