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Juli2301 [7.4K]
2 years ago
15

An electric dipole generates an electric field in the space around it what do all of the electric field lines have in common?

Physics
1 answer:
Firdavs [7]2 years ago
5 0

C. All lead from the positive charge to the negative charge

Explanation:

The electric field lines in an electric dipole all lead from the positive charge to the negative charge.

  • An electric field is the region of space where electric force is felt the most.
  • The lines of force originates from the positive charge and terminates at the negative pole.
  • Line of force do not intersect with one another.
  • when a body is place in the force field, it feels the impart of the force.

learn more:

Capacitors brainly.com/question/10427437

#learnwithBrainly

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<span>Kirchhoff's laws apply to AC circuits to either two cases: instantaneousneous values of currents and voltages or to complex values of currents and voltages. However, this never applies to: rms values of currents and voltages. Kirchoff's law relates to the current, voltage and resistance to multiple nodes</span>
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In " m a x f o r t e d u c a t i o n " . what is probability of vowels.​
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Why is it important to know how fast a roller coaster travels at certain points on the track?
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Read 2 more answers
3. What is the gravitational force between a 70 kg physics student and her 1 kg textbook, at a distance of 1 meter? (This number
Rina8888 [55]

ANSWER

\begin{equation*} 4.67*10^{-9}\text{ }N \end{equation*}

EXPLANATION

Parameters given:

Mass of the student, M = 70 kg

Mass of the textbook, m = 1 kg

Distance, r = 1 m

To find the gravitational force acting between the student and the textbook, apply the formula for gravitational force:

F=\frac{GMm}{r^2}

where G = gravitational constant

Therefore, the gravitational force acting between the student and the textbook is:

\begin{gathered} F=\frac{6.67430*10^{-11}*70*1}{1^2} \\  \\ F=4.67*10^{-9}\text{ }N \end{gathered}

That is the answer.

6 0
1 year ago
A transformer has a secondary voltage of 140 volts and a secondary current of 3.5 amps. if the primary current is 10 amps, what
Lynna [10]

For an ideal transformer power loss is assumed to be zero

i.e. the power in primary coil due to input voltage must be equal to power in secondary coil due to output voltage

this can be written in form of equation

V_1 i_1 = V_2 i_2

here we know that

V_2 = 140 volts

i_2 = 3.5 A

i_1 = 10 A{/tex]now we will use above equation[tex]140*3.5 = 10 * V_1

V_1 = 49 volts

So primary coil voltage is 49 Volts

7 0
3 years ago
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