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dimulka [17.4K]
3 years ago
12

matt built a boat with a mass of 320g. When he tried it out, he found that it displaced 260g of water. did the boat sink or floa

t? Explain
Physics
1 answer:
Flauer [41]3 years ago
4 0

When we put an object inside the water then the submerged part of the object will displace water.

this weight of displaced water is known as buoyancy force on the object

Now as we know the principle of flotation if buoyancy force due to fluid on the object is more than weight then object will easily float

So here we can say that

F_b > W

now here we know that buoyancy force is the weight of liquid which is displaced and that weight must be more than weight of object for flotation

So here we can say

So here we know that mass of object is 320 g

mass of liquid displaced 260 g

here

mass of liquid displaced < mass of object

So it will not float and it will sink

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Two light waves, initially emitted in phase, will interfere constructively with maximum amplitude if the path-length difference
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Two light waves will interfere constructively if the path-length difference between them is a whole number.

<h3>SUPERPOSITION</h3>

The principle of superposition state that, when two or more waves meet at a point, the resultant displacement at that point is equal to the sum of the displacements of the individual waves at that point.

Interference of waves can either be constructive, or destructive.

The two light waves, initially emitted in phase, will interfere constructively with maximum amplitude if the path-length difference between them is a whole number of wavelenght 1λ, 2λ, 3λ, 4λ etc

The equivalent phase differences between the waves will be 2\pi or 360 degrees, 4\pi or 720 degrees, 6\pi 1080 degrees etc

Therefore, the two light waves, initially emitted in phase, will interfere constructively with maximum amplitude if the path-length difference between them is a whole number.

Learn more about Interference here: brainly.com/question/25310724

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2 years ago
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Arbeitsauftrag 2
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Explanation:

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3 years ago
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Lera25 [3.4K]
We have to calculate the impulse of a hockey puck.
Imp = m * ( v 1 - v 2 ) = m * Δ v
v 1 = - 10 i m/s,
v 2 = ( 20 * cos 40° ) i + ( 20 * sin 40° ) j =
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Δ v = ( 15.32 i + 12.855 j ) - ( - 10 i ) =
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