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tiny-mole [99]
2 years ago
8

2. You will need a magnifying glass and a small piece of scrap paper for this demonstration. a. Go outside on a sunny day and pu

t the piece of paper on a patch of asphalt, concrete, or a large flat rock. Make sure there is no other combustible material or debris in the vicinity. b. Hold the magnifying glass so it is close to the paper, with rays of sunlight shining through it. Move the magnifying glass side to side and close or away from the paper until the most concentrated ray of light is shining on the paper. This is the focal point for that magnifying glass. c. Measure the distance between the focal point and magnifying glass. This is the focal length for that magnifying glass. (Be careful; if you hold the magnifying glass in that place for long enough, the paper will catch fire. Do not ever do this on your skin or clothing, as it can cause serious burns.) d. Now take the magnifying glass inside and use it to look at the words in a book. What is the focal length now?
Physics
1 answer:
andrew-mc [135]2 years ago
4 0

The focal length of a magnifying glass is the distance between the focal point and optical centre of the magnifying glass.

<h3>Focal length</h3>

The focal length, f is the distance from a lens or mirror to the focal point, F.

This is the distance from a lens or mirror at which parallel light rays will meet for a converging lens or mirror or appear to diverge from for a diverging lens or mirror.

A magnifying glass is a converging lens which produces a enlarged, erect and virtual image when an object is placed between the focal point and optical centre.

A magnifying glass will bring to focus at a point sun rays which can cause the paper to catch fire if it is held in place for long.

This point at which the most concentrated ray of light is shining on the paper, is the focal point for that magnifying glass.

Therefore, the focal length of a magnifying glass is the distance between the focal point and optical centre of the magnifying glass.

Learn more about about focal length at: brainly.com/question/25779311

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timama [110]

Answer:

Answer: C

explanation:

They could be same or different

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|-5|,|-5| = 5,5

|-5|,|5| = 5,5

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4 years ago
I feel dvmb for asking this question but... help? Please?
VMariaS [17]

<u>Force</u>, it can speed up or slow down an object which can change the direction in which an object is moving.

8 0
3 years ago
What sort of process converts the mechanized energy in the ocean into electricity?
allochka39001 [22]
I think it is the wave energy. 
Wave energy also known as the ocean energy is the energy harnessed from the ocean or sea waves. It is a source of power that comes from the endless march of the waves as they roll into the shore then back out. Using wave energy is advantageous as they are environmental friendly as there are no harmful byproducts, and also the energy from waves can be taken directly into electricity-producing machinery and used to power generators. 
5 0
3 years ago
A uniform plank of length 6.1 m and mass 33 kg rests horizontally on a scaffold, with 1.6 m of the plank hanging over one end of
salantis [7]

Answer:

Explanation:

consider the principle of moment

when a system is in equilibrium, the clockwise moment (torque) about the pivot is equal to the counterclockwise moment ( torque). Since the plank is uniform the weight of the plank act at the middle which = 6.1 m / 2 = 3.05 m

the distance that can support the weight of the man = d

mass of the man = 70

70 × d = 33 × ( 3.05 - 1.6)

d = 47.85 / 60 = 0.798 m, if the man work beyond this point he will fall.

8 0
3 years ago
A Carnot air conditioner takes energy from the thermal energy of a room at 63°F and transfers it as heat to the outdoors, which
vodomira [7]

Answer:

For the Carnot air conditioner working as a heat pump between 63 and 100°F , It would transfer 3.125 Joules of heat for each Joule of electric energy supplied.

Explanation:

The process described corresponds to a Carnot Heat Pump. A heat pump is a devices that moves heat from a low temperature source to a relative high temperature destination. <em>To accomplish this it requires to supply external work</em>.

For any heat pump, the coefficient of performance is a relationship between the heat that is moving to the work that is required to spend doing it<em>.</em>

For a Carnot Heat pump, its coefficient of performance is defined as:

COP_{HP}=\frac{T_H}{T_H-T_L} Where:

  • T is the temperature of each heat deposit.
  • The subscript H refers to the high temperature sink(in this case the outdoors at 100°F)
  • The subscript L refers to the low temperature source (the room at 63°F)

Then, for this Carnot heat pump:

COP_{HP}=\frac{T_H}{T_H-T_L}=\frac{100°F}{100°F-63°F}=3.125

So for each 3.125 Joules of heat to moved is is required to supply 1 Joule of work.

3 0
3 years ago
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